I believe this this the function.
![f(x) = {5}^{x - 5}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%7B5%7D%5E%7Bx%20-%205%7D%20)
then
![f(x) = {5}^{2 - 5}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%7B5%7D%5E%7B2%20-%205%7D%20)
then
![f(x) = {5}^{ - 3}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%20%7B5%7D%5E%7B%20-%203%7D%20)
then
![y = \frac{1}{125}](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B125%7D%20)
Corrected Question
The volume of air inside a rubber ball with radius r can be found using the function V(r) = four-thirds pi r cubed. What does V(5/7) represent?
Answer:
(B)the volume of the rubber ball when the radius equals five-sevenths feet
Step-by-step explanation:
The Volume of a sphere of radius r can be found using the formula:
![V(r)=\dfrac43 \pi r^3](https://tex.z-dn.net/?f=V%28r%29%3D%5Cdfrac43%20%5Cpi%20r%5E3)
Therefore comparing the expression:
with V(r):
![Radius, r=\dfrac57](https://tex.z-dn.net/?f=Radius%2C%20r%3D%5Cdfrac57)
Thus,
is the volume of a ball of radius
feet.
The correct option is B.
Answer:
-1/12
Step-by-step explanation:
change divide sign to multiply by reciprocating
Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
__
f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
__
g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).
Answer:
Step-by-step explanation:
50,000
I think