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tamaranim1 [39]
3 years ago
14

The force needed to lift an object is equal in size to the gravitational force on the object. How much work is done in lifting a

n object that has a mass of 5 kg a vertical distance of 2 m?
Please help! I offer many points for an answer!!!!
Physics
2 answers:
DanielleElmas [232]3 years ago
6 0

Answer:

Work done in lifting the object = 98 J

Explanation:

Work: Work can be defined as the product of force and distance.

The S.I unit of work is Joules (J).

Mathematically it can be expressed as

W = F × d................. Equation 1

Where W = work done, F = force needed to lift the object, d = distance

The gravitational force on the object = Weight of the object

Weight of the object = mg .................. Equation 2

Where m = mass of the object, g = acceleration due to gravity

Given: m = 5 kg,

Constant: g = 9.8 m/s²

Substituting these values into equation 2

Weight of the object = 5 × 9.8

Weight of the object = 49 N

Since weight of the object = force needed to lift the object,

F = 49 N

<em>Also Given: d = 2 m</em>

Substituting these values into equation 1

W = 49 × 2

W = 98 J

Work done in lifting the object = 98 J

Minchanka [31]3 years ago
5 0

work = force ×displacement

force=5 kg × 1000 × 10 ms -2

displacement=2 m

work=100000 J

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The boiling point of sulfur is 444.6 celsius .sulfur melting point is 586.1 fahrenheit lower than its boiling?
rewona [7]

Answer:

(a) Melting point is 136.8°C

(b) Melting point is 278.24°F

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Explanation:

(a) 586.1°F = 5/9(586.1 - 32)°C = 307.8°C

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7 0
3 years ago
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D, the acceleration  of A is twice that of b.

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What is the work done by the electric force to move a 1 c charge from a to b?
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Answer:

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