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3 years ago

BRAINLIEST!!!PLEASE HELP

Physics

1 answer:

olasank [31]3 years ago

5 0

I believe its A
\

By inductive and deductive reseachhhhh

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What makes silver and gold different by using the terms atom and element

djyliett [7]

Silver is classified as a precious metal.

Where Gold is classified as transition metal.

Silver has about 47 protons and Gold has way more- about 79 protons.

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3 years ago

A weightlifter can exert an upward force of 3750 N. If a dumbbell has a mass of 225 kg, what is the maximum number of dumbbells

MrRissso [65]

Answer:

10 dumbbells

Explanation:

First we need to calculate the gravity on the moon.

0.166 x 9.8 m/s² = 1.627 m/s² (the gravity is 0.166 times the Earth's gravity)

Taking this acceleration due to gravity, and multiplying it by the mass of a single dumbbell.

F = m x a

F = (225 kg) x (1.627 m/s²)

F = 366.075 N (the amount of force exerted by the dumbbell)

Taking the weightlifter's total upward force and dividing it by the force exerted by one dumbbell, we can calculate the amount of dumbbells that can be carried.

(3750 N) / (366.075 N)

= 10.24 dumbbells (but since there cannot be a fraction of a dumbbell, the answer is 10 dumbbells).

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3 years ago

A 20 kg wagon is pulled along the level ground by a rope inclined at 30 degree above the horizontal. A friction force of 30 N op

Elan Coil [88]

(a) 34.6 N

To solve the problem, we have to analyze the forces acting along the horizontal direction.

We have:

- Forward: the component of the pull parallel to the ground, which is

$F cos \theta$

where

F is the magnitude of the pull

$\theta=30^{\circ}$ is the angle

- Backward: the force of friction, which is

$F_f = 30 N$

So, the equation of motion is

$F cos \theta - F_f = ma$

where

m = 20 kg is the mass of the wagon

a is the acceleration

In this part, the wagon is moving at constant speed, so a =0 and the equation becomes

$F cos \theta - F_f = 0$

Therefore, we can find the pulling force:

$F=\frac{F_f}{cos \theta}=\frac{30}{cos 30}=34.6 N$

(b) 43.9 N

In this case, the acceleration is

$a=0.40 m/s^2$

So, the equation of motion in this case is

$F cos \theta - F_f = ma$

So this time we have to take into account the term (ma).

Using the same data as before:

m = 20 kg

$\theta=30^{\circ}$

$F_f = 30 N$

We find the new magnitude of F:

$F=\frac{ma+F_f}{cos \theta}=\frac{(20)(0.40)+30}{cos 30}=43.9 N$

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3 years ago

Stella is driving down a steep hill. she should keep her car __________ to help _________.

Softa [21]

Answer:

Stella is driving down a steep hill. She should keep her car in a lower gear to help slow her vehicle.

Explanation:

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3 years ago

Properties of convex mirror

Ahat [919]

Answer:

The image result of an object reflected by a convex mirror is typically virtual, upright, and smaller. Discover how moving the object farther away from the mirror's surface affects the size of the virtual image formed behind the mirror

Explanation:

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3 years ago