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stepan [7]
3 years ago
14

Simple pendulum, is show in several states In case A the mass is travelling back down to the bottom and is in between the bottom

and its max height. In case B the mass is at its max height and has a speed of zero. In case C the ball is at its lowest position which of the following statements about the magnitude of the mass's angular acceleration is true? Grade Sun O
It is maximum in case A O
It is maximum in case B O
It cannot be determined O
It is zero in all cases. O
It is maximum in case C
It is equal in all cases, but is non-zero
Physics
1 answer:
uysha [10]3 years ago
3 0

The angular acceleration is maximum in case C

Explanation:

The motion of the bob in the simple pendulum is a portion of a circular motion. In a circular motion, the angular acceleration is related to the tangential acceleration by

a=\alpha r

where

a is the tangential acceleration

\alpha is the angular acceleration

r is the radius (the length of the pendulum)

Moreover for a pendulum, the tangential acceleration is given by the component of the acceleration of gravity in the tangential direction, so

a=g sin \theta

where

g is the acceleration of gravity

\theta is the angle of the pendulum with the vertical

So we have

\alpha = \frac{g sin \theta}{r}

Since g and r are constant, we see that the angular acceleration is proportional to the angle: the larger the angle, the larger the angular acceleration, and the smaller the angle, the smaller the angular acceleration.

Therefore, the angular acceleration is maximum when the pendulum is at its maximum height, and zero when it is at the lowest position. So, the correct statements are

It is maximum in case C

Learn more about periodic motion:

brainly.com/question/5438962

#LearnwithBrainly

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3 years ago
Select the correct equations that show that the gravitational potential energy of a 1000-kg boulder raised 6 m above ground leve
wel

Answer:

U = mgh

Explanation:

The gravitational potential energy of an object is defined as:

U=mgh

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For the boulder in the problem,

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4 years ago
A man carries a load of 20N on his head over a horizontal distance of 20 m how much work is done by the man
sdas [7]

Work done in horizontal direction = 0 as the potential energy is not changed and the change in kinetic energies : initial and final - is zero.


work done when the person carries the suitcase in vertical direction =

  = m g h = change in potential energy = 30 kg * 9.8 m/sec/sec * 10 m

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=============

There is a force F1 lifting the body upwards. There is Weight W = m g pulling the body downwards.  The net force F2 on the body is upwards with acceleration a.


  F2 = m a  = F1 - W = F1 - m g

          a =  F1 / m - g


Work done by Force F1 with which the object is lifted = F1 . s = 230 Joules

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Net Acceleration of the body = a = F1 / m - g = 115/10 - 10  = 1.5 m/sec/sec

==========================


 m = 2 kg          F = 8 Newtons        t = 12 sec

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v = u + a t = 0 + 4 * 12 = 48 m/sec


kinetic energy = 1/2 m v² = 1/2 * 2 * 48 * 48 = 48² Joules



Read more on Brainly.in - https://brainly.in/question/71130#readmore


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The answer you are looking for is D. 245N. 
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