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olasank [31]
3 years ago
8

Jen has 2 meters of taffy. She wants to give each of her three best friends in equal amount of taffy how many centimeters of taf

fy will each friend get it? Write your answer as a fraction
Mathematics
1 answer:
Oksanka [162]3 years ago
7 0
Here is the solution of the given problem above.
Given: 2 meters = The length of the taffy that Jen has
           1/3 of two meters = measurements of each of her three best friends
           ? = 1/3 of two meters
           ? = 1/3 of two meters converted to centimeters
First, we need to get how long 1/3 of 2 meters is. So 2 multiplied by 1/3 is 0.67 meters. So each of her friends gets 0.67 meters. And 0.67 meters in centimeters is 67 meters. 1 meter = 100 centimeters. 
In fraction, each friend will get 67/200 centimeters. 
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(45 1/3 + 6 1/3)+38 2/3 ?
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The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of 7 minutes and a stand
julsineya [31]

Answer:

There is a 2.28% probability that it takes less than one minute to find a parking space. Since this probability is smaller than 5%, you would be surprised to find a parking space so fast.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.

Also, a probability is unusual if it is lesser than 5%. If it is unusual, it is surprising.

In this problem:

The length of time it takes to find a parking space at 9 A.M. follows a normal distribution with a mean of 7 minutes and a standard deviation of 3 minutes, so \mu = 7, \sigma = 3.

We need to find the probability that it takes less than one minute to find a parking space.

So we need to find the pvalue of Z when X = 1

Z = \frac{X - \mu}{\sigma}

Z = \frac{1 - 7}{3}

Z = -2

Z = -2 has a pvalue of 0.0228.

There is a 2.28% probability that it takes less than one minute to find a parking space. Since this probability is smaller than 5%, you would be surprised to find a parking space so fast.

5 0
3 years ago
Aluminium coated dewars are cylindrical flasks used to safely store and transport liquid nitrogen, dry ice etc. A company manufa
Nitella [24]

This question is Incomplete because it lacks the diagram showing the containers as well as the required options. Find attached to this answer the appropriate diagram.

Complete Question

Aluminium coated dewars are cylindrical flasks used to safely store and transport liquid nitrogen, dry ice etc. A company manufactures such dewars of different sizes. Shown here are two dewars, both of the same height but of different diameters. How much aluminium will be required to cover Dewar A compared to that required for Dewar B? (Note: The base and the lid are NOT made up of aluminium.)

A) 1/3 times

B) 3 times

C) 9 times

D) The same amount of aluminum will be required.

Answer:

B) 3 times

Step-by-step explanation:

From the question, we are told that we are to find the amount of aluminum to cover Dewar A and B , we are also told that the base and the lid are not covered with aluminum.

From this information, we can determine that we are to find the curved or Lateral surface area of the cylinder because the base and lid are not included

The curved surface area of a cylinder is calculated as 2πrh

We told that both cylinders have the same height. Hence,

For Dewar A

We have Diameter of 30 cm, radius = Diameter ÷ 2 = 30cm ÷ 2 = 15cm.

Height = h

The curved surface area = 2πrh

= 2 × π × 15 ×h

= 30πhcm²

For Dewar B

We have Diameter of 10 cm, radius = Diameter ÷ 2 = 10cm ÷ 2 = 5cm.

Height = h

The curved surface area = 2πrh

= 2 × π × 5 ×h

= 10πhcm²

When we compare the curved surface Dewar A to the curved surface area of Dewar B

Dewar A : Dewar B

30πhcm² : 10πhcm²

3(10πhcm²) : 10πhcm²

From the above comparison, we can see that 3 times more aluminum is required to cover Dewar A compared to Dewar B.

6 0
3 years ago
NEED HELP ASAP PLEASE
Igoryamba

Answer:

The answer would B!

Hope this helps

Please give me Brainliest

3 0
3 years ago
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