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Sindrei [870]
3 years ago
11

In how many different ways can a jury of 12 people be randomly selected from a group of 40 people?

Mathematics
1 answer:
kupik [55]3 years ago
3 0

Answer:

There are 5,586,853,480 different ways to select the jury.

Step-by-step explanation:

The order is not important.

For example, if we had sets of 2 elements

Tremaine and Tre'davious would be the same set as Tre'davious and Tremaine. So we use the combinations formula.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In how many different ways can a jury of 12 people be randomly selected from a group of 40 people?

Here we have n = 40, x = 12.

So

C_{40,12} = \frac{40!}{12!(28)!} = 5,586,853,480

There are 5,586,853,480 different ways to select the jury.

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Answer:

(a) 896

(b) 1000

(c) 910

Step-by-step explanation:

Number of women = 8

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(b) 2 of the women refuse to serve together.

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1000

(c)1 man and 1 woman refuse to serve together.

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910

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x^2+9x+8

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