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Valentin [98]
3 years ago
15

Draw a point that shows the value of the 2020th dvddvd. label it 1. draw a point that shows the willingness to pay for the 1010t

h dvddvd. label it 2. draw an arrow to show the consumer surplus on the 1010th dvddvd. label it cs.
Mathematics
1 answer:
Elina [12.6K]3 years ago
6 0
Very hard question. .....
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Ms. Jones is making the yearbook. She has 7 pages with 153 photos on each
Rzqust [24]

Answer:

1,071

Step-by-step explanation:

7 × 153 = 1071

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3 years ago
Solve the inequality. Graph the solution set.<br> 5x - 6 &gt; 4x - 8
aleksandrvk [35]

Answer:

Step-by-step explanation:

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6 0
3 years ago
The net weights (in grams) of a sample of bottles filled by a machine manufactured by Edne, and the net weights of a sample fill
IRINA_888 [86]

Answer:

t=\frac{(10 -7)-(0)}{\sqrt{\frac{2.268^2}{8}+\frac{1.414^2}{6}}}=3.036  

p_v =P(t_{12}>3.036) =0.0051  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Orno) is significantly higher than the mean for the group 2 (Edne).  

Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 \leq \mu_2  

Alternative hypothesis: \mu_1 > \mu_2  

Or equivalently:  

Null hypothesis: \mu_1 - \mu_2 \leq 0  

Alternative hypothesis: \mu_1 -\mu_2 > 0  

Our notation on this case :  

n_1 =8 represent the sample size for group 1 (Orno)  

n_2 =6 represent the sample size for group 2  (Edne)

We can calculate the sampel means and deviations with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_1 =10 represent the sample mean for the group 1  

\bar X_2 =7 represent the sample mean for the group 2  

s_1=2.268 represent the sample standard deviation for group 1  

s_2=1.414 represent the sample standard deviation for group 2  

If we see the alternative hypothesis we see that we are conducting a right tailed test.

On this case since the significance assumed is 0.05 and we are conducting a bilateral test we have one critica value, and we need on the right tail of the distribution \alpha/2 = 0.05 of the area.  

The distribution on this case since we don't know the population deviation for both samples is the t distribution with df=8+6 -2=12 degrees of freedom.

We can use the following excel code in order to find the critical value:

"=T.INV(1-0.05,12)"

And the rejection zone is: (1.78,infinity)

The statistic is given by this formula:  

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}+\frac{S^2_2}{n_2}}}  

And now we can calculate the statistic:  

t=\frac{(10 -7)-(0)}{\sqrt{\frac{2.268^2}{8}+\frac{1.414^2}{6}}}=3.036  

The degrees of freedom are given by:  

df=8+6-2=12

And now we can calculate the p value using the altenative hypothesis:  

p_v =P(t_{12}>3.036) =0.0051  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Orno) is significantly higher than the mean for the group 2 (Edne).  

4 0
3 years ago
HELP WHAT IS 2+2+2+2+2+2+2+2+10000000000000000000000+1111111111111111111111111111111111111111111111111111111111111111111111111-1
deff fn [24]

Answer:

1111111111111111111111100000000000000000000066666721111111111111111111126

Step-by-step explanation:

???

8 0
2 years ago
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What is the inverse of the function g(x) 3x+7/2?
Kamila [148]
Here’s the answer......

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