1.0210 is the answer
hoped this helped
<h2>
Answer with explanation:</h2>
Let
be the population mean.
By observing the given information, we have :-

Since the alternative hypotheses is left tailed so the test is a right-tailed test.
We assume that the time spend by students per day is normally distributed.
Given : Sample size : n=121 , since n>30 so we use z-test.
Sample mean : 
Standard deviation : 
Test statistic for population mean :-


Critical value (one-tailed) corresponds to the given significance level :-

Since the observed value of z (-7.79) is less than the critical value (1.2816) , so we do not reject the null hypothesis.
Hence, we conclude that we have enough evidence to accept that the college students spend an average of 4 hours or less studying per day.
Step-by-step explanation:
Solution
According to remainder theorem, when f(x) is divided by (x+2), Remainder =f(−2)
f(x)=5x3+2x2−6x+12
f(−2)=5(−2)3+2(−2)2−6(−2)+12
=5×−8+2×4+12+12
=−40+32=−8
∴ Remainder=−8
77+72=149
149/2=74.5
through the process of elimination, I found that Jim needs to get an 88 or higher to receive an average of 79 or greater.
77+72+88=237
237/3=79
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