1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
Answer:

Step-by-step explanation:
step 1
Find the value of x
we know that
If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent
In this problem we have that
∆EGF~∆EML
so

substitute the given values

solve for x



step 2
Find MG
we know that

substitute

Answer:
m is the right answer
Step-by-step explanation:
no step hope yu mark me as brainliest
Answer:
3 chocolate bars, and 2 graham crackers
Someone forgot the marshmallows...... :P
Step-by-step explanation:
Chocolate bars = 8 pack
Graham Crackers = 12pack
To have no crackers or chocolate left over, we need to find LCM
Factors of 8:
8, 16, 24, 32, 40, 48, 56, 72....
Factors of 12:
12, 24, 36, 48, 60, 72
The smallest LCM is 24
Chocolate bars:
24/8 = 3
Graham Crackers:
24/12 = 2
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K