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Arlecino [84]
2 years ago
12

Hey.... sorry for that, are you still mad at me ?​

Mathematics
2 answers:
Digiron [165]2 years ago
8 0

Answer:

do u mean me???

elena55 [62]2 years ago
3 0

Answer:

?????

Step-by-step explanation:

Wha tttttttttttttttttttttttttttttttttttttttttt

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Which of the following is the perimeter of a triangle with side lengths of 7 inches, 8 inches, and 13 inches?
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I need help ASAP please with all of them
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The school sold 300 tickets to the theatre performance. They sold adult tickets for $9 each and student tickets for $6 each. The
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Your answer is.....

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Mark it as brainlist answer . follow me for more answer.

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Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.
Andre45 [30]

Answer:

Option d)  5 to the power of negative 5 over 6 is correct.

\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}

Above equation can be written as 5 to the power of negative 5 over 6.

ie, 5^\frac{\bf -5}{\bf 6}

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}

Above equation can be written as 5 to the power of negative 5 over 6.

7 0
3 years ago
Write the sentence as an equation. 143 divided by g is g
mash [69]

Answer:

143÷g=g

Kinda easy.

I hope this is what you meant.

And I hope this helps you! ;P

6 0
3 years ago
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