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ANSWER
A) -1
EXPLANATION
The average rate of change of the given quadratic function on the interval 0 ≤ x ≤4 is the slope of the secant line connecting the points (0,f(0)) and (4,f(4)).
That is the average rate of change is:
From the graph, f(0) is 0 and f(4) is -4.
We plug in these values to obtain;
This simplifies to;
Hence the average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1
A) -1
EXPLANATION
The average rate of change of the given quadratic function on the interval 0 ≤ x ≤4 is the slope of the secant line connecting the points (0,f(0)) and (4,f(4)).
That is the average rate of change is:
From the graph, f(0) is 0 and f(4) is -4.
We plug in these values to obtain;
This simplifies to;
Hence the average rate of change for the given quadratic function whose graph is shown on 0≤x≤4 is -1
We will start with plotting the x coordinates and y coordinates on the graph
The points 1, 2; 2, 2; 3, 2; 4, 2 have been plotted on the graph which has been attached as an image to the solution.
We can see that the value of y is staying constant (2) for all values of x.
Hence, the points represent the equation y = 2.
