Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
Step-by-step explanation:
theres 4reds every 50 so do 50x4 then you times that by four 50x4=200 so do 200x4=800
The answer is only C and D
Answer:
Step-by-step explanation:
To solve equations like this you need to to get x by itself.
So, Let's multiply both sides by 5 to get rid of 5.
3x/5 *5 = 30 * 5
= 3x = 150
Now we divide both sides by 3 to get x by itself,
3x/3 = 150/3
x = 50
50/2.5=
20
Unit rate is 20 miles per gallon