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ehidna [41]
3 years ago
5

Evaluate the expression. –5g – 6 for g = –2

Mathematics
2 answers:
Artist 52 [7]3 years ago
6 0

Answer:

4

Step-by-step explanation:

Given that:

= –5g – 6

put g = -2

= -5(-2) - 6

= 10 - 6

= 4

i hope it will help you!

zaharov [31]3 years ago
3 0

Answer: 4

Step-by-step explanation:

-5g - 6 when g = -2

-5 (-2) - 6

-5 * -2 = 10

10 - 6 = 4

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What is the formula for ANOVA
Sergio039 [100]
P = 3
n = 5
N = 15
<span><span><span>x </span><span>¯ </span></span> </span> = 16
<span><span>SST</span> </span>  = <span><span>∑n(x−<span><span>x </span><span>¯ </span></span><span><span>) </span><span>2 </span></span></span> </span>
<span><span>SST</span> </span> = <span><span>5(12−16<span><span>) </span><span>2 </span></span>+5(16−16<span><span>) </span><span>2 </span></span>+11(20−16<span><span>) </span><span>2 </span></span></span> </span>
= 160
<span><span>MST</span> </span> = <span><span><span><span>SST</span><span>p−1</span> </span> </span> </span>
<span><span>MST</span> </span> = <span><span><span>160<span>3−1</span> </span> </span> </span>
= 80
<span><span>SSE</span> </span> = <span><span>∑(n−1)<span><span>S </span><span>2 </span></span></span> </span>
SSE = 4*4 + 4*1 + 4*16
= 84
<span><span>MSE</span> </span> = <span><span><span><span>SSE</span><span>N−p</span> </span> </span> </span>
<span><span>MSE</span> </span> = <span><span><span>84<span>15−3</span> </span> </span> </span>
MSE = 7
<span>F </span> = <span><span><span><span>MST</span><span>MSE</span> </span> </span> </span>
<span>F </span> = <span><span><span>807 </span> </span> </span>
= 11.429
 

8 0
3 years ago
(10x – 2) - (2x - 7)<br> O 8x + 5<br> O 12.2 + 5<br> o 12c - 9<br> O 83 -9
Yuki888 [10]

Answer:

the first one

8x+5

Step-by-step explanation:

10x-2-2x+7= 8x+5

8 0
2 years ago
2x+3 what is x I don’t know
Triss [41]

Answer:

2x + 3 \\  or \: 2x =  - 3 \\ or \: x =   - \frac{3}{2}  \\ therefore \:  \: the \: value \: of \: x \: is \:  -  \frac{3}{2}

<h3> I hoped this helps you ☺️☺️ </h3>

Thank you ☺️☺️

8 0
3 years ago
We defined the operation of concatenation for sets of strings on p. 10, AB = { XY | X ∈ A and y ∈ B}Are the regular sets closed
lakkis [162]

Answer and Explanation:

Solution: The operation of concatenation for a set of string on p. and the set is

     AB = {XY | X ∈ A and y ∈ B}.

We need to satisfy all these following properties to find out the standard set is closed under concatenation.

1- Union of two standard sets also belongs to the classic collection. For example, A and B are regular. AUB also belongs to a regular group.

2- Compliment of two standards set A and B are A’ and B’ also belonging to the standard set.

3- Intersection of two standards set A and B is A∩B is also a regular set member.

4- The difference between two regular sets is also standard. For example, the difference between A and B is A-B is also a standard set.

The closure of the regular set is also standard, and the concatenation of traditional sets is regular.

3 0
3 years ago
0.34 times 10 with an exponet 3
STALIN [3.7K]

Answer: 340

Step-by-step explanation:

Because if you multiply 0.34x 10 to the 3rd power you get 340

Hope This helped :))

7 0
2 years ago
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