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3 years ago

The steps below show the work of a student used to calculate the number of yards in 804.5 meters.

1 answer:

3 0

The first step is wrong since 804.5 meters he should have divided that by the 1609 conversation and determined that 804.5 meters is only 1/2 mile, not 2

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a 5-liter cleaning solution contains 30% bleach. a 3-liter cleaning solution contains 50% bleach. what percent of bleach obtaine

vladimir1956 [14]

Answer:

First find the 30% of 5-liter cleaning solution.

3/10*5L=1.5L

We know 50% of 3L is 1.5.

If we add, the two bleach percentages, we get 3L of bleach.

When we add the two containers of cleaning solution, we get 8L.

The percentage of bleach in the mixture will be the ratio 3/8 expressed as a %.

3/8*100=37.5% of the cleaning solution will be bleach.

Answer: 37.5%

4 0

3 years ago

Mary and ann made drinks for a picnic. one used 3 cans juice concentrate and 8 cans water. the other 5 cans juice concentrate an

Sveta_85 [38]

I would think that it would be the 3:8 one because if you do the math, 8-3 is 5 and 12-5 is 7. The only reason Im doing it this way is because its the only way I can set it up.

so you have more of a difference with the 12:5 one and less of a difference with the 3:8.

I hope I helped a bit

4 0

3 years ago

Help me out please???

11111nata11111 [884]

90 pb hope it helped ssdyacyd ja hcdke uvsk fideciscwtory264994972076159467577396257242

7 0

3 years ago

The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6

viktelen [127]

Answer:

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

The proportion of contracts involved between five and 10 inclusive bidders is 0.5.

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders No. contracts Relative frequency of contracts

2 6 6/102=0.0588

3 20 20/102=0.1961

4 24 24/102=0.2353

5 18 18/102=0.1765

6 13 13/102=0.1275

7 7 7/102=0.0686

8 5 5/102=0.049

9 6 6/102=0.0588

10 2 2/102=0.0196

11 1 1/102=0.0098

Total 102

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

We have to find proportion of contracts involved between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The proportion of contracts involved between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10= Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

8 0

3 years ago

A line segment is defined as a part of a straight line connecting two points called

Feliz [49]

Answer: D

Step-by-step explanation:

7 0

3 years ago