Answer:
a²- b²=(a+b)(a-b)
a² + b²=(a+b)²-2ab or (a-b)²+2ab
(a + b)³=a³+3a²b+3ab²+b³ or, a³+b³+3ab(a+b)
Answer:
sin^2(θ)+cos^2(θ)=1
Step-by-step explanation:
We know that the statement above is true because of the Pythagorean identity theorem, which states the aforementioned equation. If you solve the equation for 1 you get the same equation.
To do this first multiply both sides by cos(θ), this gives you (cos^2θ)/1+sinθ = 1-sinθ
Then, multiply both sides by sinθ. This equals cos^θ=1-sin^2θ.
Finally, add sin^2θ to both sides. This equals the final answer of cos^2θ+sin^2θ=1. Which is true.
I think i figured it out so it’s 0.37 :))))))))
Interesting question. Let the 2 unknown sides be x and x+1.
Then (11 m)^2 + x^2 = sum of the squares of the 2 shortest sides
= (x+1)^2
121 + x^2 = x^2 + 2x + 1. Then 121 = 2x + 1, and 2x = 120, or x = 60.
Then the hyp. has length 60+1= 61.
We must check these results. Using the Pyth. Thm. (a^2 + b^2 = c^2),
11^2 + 60^2 = 61^2
121 + 3600 = 3721 This is true, so our answers are correct.
The longer side is 60 and the hyp. has length 61.
Answer:
Step-by-step explanation: