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sveta [45]
3 years ago
15

What's the area of the shaded region?

Mathematics
1 answer:
satela [25.4K]3 years ago
8 0
Do you remember how to find the area of a circle ?

Big Fat Hint:  The area of a circle is  (pi) x (its radius)² .

Can you find the area of the big circle ... the one with radius = 18 m ?
Do that.  The whole big circle, just as if there was nothing inside it, and
no shaded region.
I'll wait.


Now, can you find the area of the small circle ... the one with radius = 12 m ?
Do that.
I'll wait.

The area of the shaded region is just

         (the area of the big circle) minus (the area of the small circle) !


I got 180 pi or roughly 565.2 m².  I could be wrong.  You should check it.
You might be interested in
The length of a rectangle is 4 yd longer than its width.
xenn [34]

Answer:

Area = 77 yd²

Step-by-step explanation:

Width = w

Length = w+4

Perimeter =36

Perimeter = L + L + w + w

36 = w+4+w+4+w+w

4w+8 =36

Subtract 8 from both sides

4w = 36 - 8

4w =28

Divide both sides by 4

W= 28/4

W= 7yd

Therefore length = w+4 = 7+4 = 11 yd

Area = length x width

Area = 11× 7

Area = 77 yd²

I hope this was helpful, please mark as brainliest

4 0
3 years ago
Find the average rate of change for f(x) = x2 + 9x + 18 from x = -8 to x = -2.
aksik [14]
Need more information!!!!
5 0
4 years ago
According to Nielsen Media Research. of all the U.S. households that owned at least one television set, 83% had two or more sets
Rudik [331]

Answer:

The proportion of U.S. households that owned two or more televisions is 83%.

Step-by-step explanation:

To determine whether the proportions of U.S. households that owned two or more televisions is less than 83% or not let us perform a hypothesis test for single proportion.

<u>Assumptions:</u>

The sample size (<em>n</em>) selected by the local cable company is 300 which is quite large. Then according to the Central limit theorem the sampling distribution of sample proportion follows a normal distribution with mean <em>p</em> and standard deviation \sqrt{\frac{p(1-p)}{n} } .

Since the sampling distribution of sample proportions follows a normal distribution use the <em>z</em>-test for one proportion to perform the test.

<u>The hypothesis is:</u>

H_{0} : The proportion of U.S. households that owned two or more televisions is 83%, i.e. p=0.83

H_{1} :The proportion of U.S. households that owned two or more televisions is less than 83%, i.e. p< 0.83

<u>Decision Rule:</u>

At the level of significance α = 0.05 the critical region for a one-tailed <em>z</em>-test is:

\\ Z\leq -1.645\\

**Use the <em>z</em> table for the critical values.

So, if \\ Z\leq -1.645\\ the null hypothesis will be rejected.

<u>Test statistic value:</u>

z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

Here \hat{p} is the sample proportion.

Compute the value of \hat{p} as follows:

\hat{p}=\frac{X}{n} \\=\frac{240}{300}\\ =0.80

Now compute the value of the test statistic as follows:

z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}\\=\frac{0.80-0.83}{\sqrt{\frac{0.83*(1-0.83)}{300} } } \\=-1.383

The test statistic is -1.383 which is more than -1.645.

Thus, the test statistic lies in the acceptance region.

Hence we fail to reject the null hypothesis.

<u>Conclusion:</u>

At 0.05 level of significance we fail to reject the null hypothesis stating that the proportion of U.S. households that owned two or more televisions is  83%.

6 0
3 years ago
Write a polynomial function of least degree with integral coefficients that has the given zeros. -5, 3i
Virty [35]

Solving for the polynomial function of least degree with integral coefficients whose zeros are -5, 3i

 

We have:
x = -5

Then x + 5 = 0

Therefore one of the factors of the polynomial function is (x + 5)


Also, we have:
x = 3i
Which can be rewritten as:
x = Sqrt(-9)
Square both sides of the equation:
x^2 = -9
x^2 + 9 = 0

Therefore one of the factors of the polynomial function is (x^2 + 9)


The polynomial function has factors: (x + 5)(x^2 + 9)
= x(x^2 + 9) + 5(x^2 + 9)

= x^3 + 9x + 5x^2 = 45

Therefore, x^3 + 5x^2 + 9x – 45 = 0

f(x) = x^3 + 5x^2 + 9x – 45

 

The polynomial function of least degree with integral coefficients that has the given zeros, -5, 3i is f(x) = x^3 + 5x^2 + 9x – 45

5 0
3 years ago
4 glasses hold 32.2 oz in all about how much does each glass hold
Rasek [7]
The answer is 9.5 because 32.2 divided by 4= 9.5
5 0
3 years ago
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