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3 years ago

Write 75 degrees in full form

Mathematics

2 answers:

swat323 years ago

4 0

75 degrees in full form is 108/5 degrees

Daniel [21]3 years ago

3 0

Um i think its from 108/5

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Graph each absolute value function. State the domain, range, and y-intercept.

Inessa05 [86]

Answer:

i. D:All real numbers

ii.R: $y\le-2$

iii. Y-int: $b=-2.5$

Step-by-step explanation:

The given function is

$y=-\frac{1}{2} |x-1|-2$

The domain of this function are the values of x that makes the function defined.

The absolute value function is defined for all real values.

The domain is all real numbers.

ii. The range refers to the values of y for which x is defined.

$y=-\frac{1}{2} |x-1|-2$

The vertex of this function is

$(1,-2)$

The function is reflected in the x-axis.

The vertex is therefore the maximum point on the graph of the function.

The range is therefore;

$y\le-2$

Or

$(-\infty,2]$

iii. To find the y-intercept, we substitute $x=0$ into the funtion.

$y=-\frac{1}{2} |0-1|-2$

$y=-\frac{1}{2} (1)-2$

$y=-2.5$

The y-intercept is $b=-2.5$

The graph is shown in the attachment.

3 0

3 years ago

Find all solutions to the equation in the interval [0, 2pi). COS X = sin 2x

Lera25 [3.4K]

Answer:

Step-by-step explanation:

cos x=sin 2x

sin 2x-cos x=0

2 sin x cos x-cos x=0

cos x(2 sin x-1)=0

either cos x=0

$x=\frac{\pi }{2},\frac{3\pi }{2}$

2 sin x-1=0

$sin x=\frac{1}{2} =sin (\frac{\pi }{6}),sin(\pi -\frac{\pi }{6} )\\x=\frac{\pi }{6} ,\frac{5 \pi }{6}$

6 0

3 years ago

In the coordinate plane, what is the length of the line segment that connects points at (0,-1) and (-7, -2)?

lilavasa [31]

Answer:100cm

Step-by-step explanation:

8 0

3 years ago

In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and

Umnica [9.8K]

Answer:

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0

3 years ago

Two angles are supplementary the measure of one angle is 4 times the measure of the other angle what is the measure of the small

noname [10]

X + y = 180
x = 4y
Plug that in and you get: 4y + y = 180
5y = 180
y = 36

If you want the larger angle, simply plug in y to x = 4y
So: x = 4(36) = 144

The smaller angle is 36 degrees, and the larger angle is 144 degrees.

7 0

3 years ago