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4 years ago

What is the value of y in the equation 2 + y = −3?

Mathematics

1 answer:

s2008m [1.1K]4 years ago

3 0

Answer:

the answer is negative 5

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The explicit formula for the geometric sequence -1/9, 1/3, -1, 3, -9, ... is -1/9(-3)^x-1 . What is the common ratio and recursi

KATRIN_1 [288]

Answer:

r=3
$\left\{\begin{array}{ccc}a_1=-\frac{1}{9}\\a_n=-3a_{n-1}\end{array}\right$

Step-by-step explanation:

Given the sequence

$-1/9, 1/3, -1, 3, -9, ...$

The common ratio is determined by the division of term by the previous term.

Common Ratio, $r=\frac{1/3}{-1/9} =\frac{-1}{1/3} =\frac{3}{-1}=-3$

A recursive formula is a formula that defines each term of a sequence using preceding term(s).

For the given sequence, the recursive formula is:

$\left\{\begin{array}{ccc}a_1=-\frac{1}{9}\\a_n=-3a_{n-1}\end{array}\right$

7 0

3 years ago

Read 2 more answers

Please somebody I need help

Goshia [24]

Answer:

Step-by-step explanation:

4 0

3 years ago

PLEASE HELP ME ILL MARK YOU AS A Brainiest <br> Quickkkkkk

AVprozaik [17]

Answer:

5 + 2q = 15

Step-by-step explanation:

The perimeter is 4 + 2 + q + (q - 1) = 15.

Add 4 + 2 then subtract the sum from both sides.

q + (q - 1) = 9

This can be simplified further by adding the "q" variables together.

2q - 1 = 9

Add 1 to both sides.

2q = 10

Divide both sides by 2 to isolate q.

q = 5

6 0

3 years ago

this formula, i represents the _____ of the loan. a. annual interest rate b. interest rate per period c. initial amount d. incid

Phantasy [73]

Answer:

b. interest rate per period

Step-by-step explanation:

We know that

Annual interest rate is APR or (r)

Po is initial amount

n is number of periods

t is time in years

A is the amount after t years

so,

i is the interest rate per period

Hence ,

answer is

i is the interest rate per period

3 0

3 years ago

There are 200 students in eleventh grade high school class. There are 40 students in the soccer team and 50 students in the bask

bekas [8.4K]

Answer:

P(A) = 0.2

P(B) = 0.25

P(A&B) = 0.05

P(A|B) = 0.2

P(A|B) = P(A) = 0.2

Step-by-step explanation:

P(A) is the probability that the selected student plays soccer.

Then:

$P(A)=\dfrac{40}{200}=0.2$

P(B) is the probability that the selected student plays basketball.

Then:

$P(B)=\dfrac{50}{200}=0.25$

P(A and B) is the probability that the selected student plays soccer and basketball:

$P(A\&B)=\dfrac{10}{200}=0.05$

P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:

$P(A|B)=\dfrac{P(A\&B)}{P(B)}=\dfrac{10}{50}=0.2$

P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.

4 0

4 years ago