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mylen [45]
3 years ago
13

Solve this: (2m+1)^2

Mathematics
2 answers:
Mrac [35]3 years ago
4 0

Answer:4m^2+4m+1

Step-by-step explanation:

(2m+1)^2=(2m+1)(2m+1)

Opening brackets we have:

4m^2+2m+2m+1

Add like terms

4m^2+4m+1

gizmo_the_mogwai [7]3 years ago
3 0

Answer:

The solution is

4m² + 4m + 1

Step-by-step explanation:

Solve this: (2m+1)²

If X² = X*X

Therefore, (2m+1)² = (2m+1) x (2m+1)

Opening the bracket (2m+1) x (2m+1)

=2m*2m + 2m*1 + 1*2m + 1*1

= 4m² + 2m + 2m + 1

Collect the like terms

= 4m² + 4m + 1

From this point, the equation can't be solved further.

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Angelina_Jolie [31]

Answer:

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8 0
3 years ago
54,36,24 whats the next term in the geometric sequence
kodGreya [7K]

Answer:

16

Step-by-step explanation:

The common ratio is 36/54 = 2/3.

So the next term is 2/3 (24) = 16.

3 0
3 years ago
H. Four businessman invested a sum of Rs.
balandron [24]

Answer:

The answers are in solutions.

Step-by-step explanation:

  • Four businessmen invested a sum of Rs. 250,000 in the ratio of 3:5:7:10 to start a new business.

(i) The amount invested by each businessman is;

<u>1^st businessman invested:</u>

<u />

\frac{3}{25}  * 250,000 = Rs. 30,000

<u>2^nd businessman invested:</u>

<u />

<u />\frac{5}{25} * 250,000 = Rs. 50,000

<u>3^rd businessman invested:</u>

<u />

<u />\frac{7}{25} *250,000 = Rs. 70,000

<u>4^th businessman invested:</u>

<u />

\frac{10}{25} *250,000 = Rs. 100,000

  • If they gained Rs. 50,000

(ii) The profit each one of them got is;

<u>1^st businessman got:</u>

<u />

<u />\frac{3}{25} * 50,000 = Rs. 6,000

<u>2^nd businessman got:</u>

<u />

<u />\frac{5}{25} *50,000 = Rs. 10,000

<u>3^rd businessman got:</u>

<u />

<u />\frac{7}{25} *50,000 = Rs. 14,000

<u>4^th businessman got:</u>

\frac{10}{25} *50,000 = Rs. 20,000

8 0
3 years ago
A triangle has side lengths of (1.3k+3.5m)(1.3k+3.5m) centimeters, (4.1k-1.6n)(4.1k−1.6n) centimeters, and (9.7n+4.4m)(9.7n+4.4m
Scorpion4ik [409]

Answer:

(5.4k+7.9m+8.1n) centimeters

Step-by-step explanation:

Given the side length of a triangle;

S1 = (1.3k+3.5m) cm

S2 = (4.1k-1.6n) cm

S3 = (9.7n+4.4m) cm

Perimeter of the triangle = S1+S2 + S3

Perimeter of the triangle = (1.3k+3.5m) + (4.1k-1.6n) + (9.7n+4.4m)

Collect the like terms;

Perimeter of the triangle = 1.3k+4.1k+3.5m+4.4m-1.6n+9.7n

Perimeter of the triangle = 5.4k+7.9m+8.1n

Hence the expression that represents the perimeter of the triangle is (5.4k+7.9m+8.1n) centimeters

5 0
3 years ago
NEED Help ASAP I Will GIVE BRAINLIST
seropon [69]
57.3 is the answer dididjwkjakz
6 0
3 years ago
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