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zlopas [31]
3 years ago
12

Take a factor out of the square root:

Mathematics
1 answer:
klasskru [66]3 years ago
8 0

Answer:

1.  |y| sqrt(10)

2.  |x| sqrt(x)

3. a^2 sqrt(a)

4.  4 |y|^3 sqrt(3)

5.  1/4 *|x| sqrt(3x)

Step-by-step explanation:

1.  sqrt(10y^2)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(y^2) sqrt(10)

|y| sqrt(10)

We take the absolute  value of y because -y*-y = y^2 and the principle square root is y

2.  sqrt(x^3)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(x^2) sqrt(x)

|x| sqrt(x)

3. sqrt(a^5)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(a^4) sqrt(a)

a^2 sqrt(a)

4.  sqrt(16 y^7)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(16) sqrt(y^6)sqrt(y)

4 |y|^3 sqrt(3)

5.  sqrt(3/16x^3)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(1/16) sqrt(x^2)sqrt(3x)

1/4 *|x| sqrt(3x)

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Solve the inequality<br>x - 3 &lt; 3x - 7.​
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6. The Grand Theater has 13,451 seats. If 15,340 people need to be seated in the theater for a music concert, write and solve
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3 years ago
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The sum of squares of two consecutive positive even integers is 52 more than their product. Find these numbers.
natulia [17]

Answer:

The first set of consecutive even integers equals (8 , 6)

The second set is ( - 8 and - 6) which also works.

Step-by-step explanation:

Equation

(x)^2 + (x + 2)^2 = (x)(x + 2) + 52            Remove the brackets on both sides

Solution

x^2 + x^2 + 4x + 4 = x^2 + 2x + 52        Collect the like terms on the left

2x^2+ 4x+ 4 = x^2 + 2x + 52                  Subtract right side from left

2x^2 - x^2 + 4x - 2x + 4 - 52  =  0          Collect the like terms

x^2 + 2x - 48 = 0                                     Factor

(x + 8)(x - 6) = 0

Answer

Try the one you know works.

x - 6 = 0

x = 6

Therefore the two integers are 6 and 8

6^2 + 8^2 = 100

6*8 + 52  = 100

So 6 and 8 is one set of  consecutive even numbers that works.    

========================

What about the other set.

x + 8 = 0

x = - 8

x and x + 2

- 8  and -8 + 2 = - 8, - 6

(- 8 )^2 + (- 6)^2 = 100

(-8)(-6) + 52 = 100

Both sets of consecutive numbers work.


5 0
3 years ago
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