A<span> DHCPOffer packet is sent to the client.</span>
Answer:
4 5 6
Explanation:
Since there is a do-while loop, you need to check the values for each iteration until the condition (Count <= X) is not satisfied.
First iteration -> Count = 1 and X = 3, Y = 1 + 3, Write Y -> 4
Second iteration -> Count = 2 and X = 3, Y = 2 + 3, Write Y -> 5
Third iteration -> Count = 3 and X = 3, Y = 3 + 3, Write Y -> 6
After the third iteration count is equal to 4 and X is equal to 3. That is why loop ends.
Answer:
Cause it fun and i have fun
call of duty and football and boxing games
Since i was 7 now im 13
with your mind
I dont know
Answer:
a defect in a software program that prevents it from working correctly
Explanation:
got it right on edge2021
Pseudocode:
import random
fetch user input on a lucky number
insert input into variable - "response"
new variable, random = randint
condition to check wheather random is our response
display results
Python Code:
import random
def main():
response = int(input("Guess my lucky number, its between 1 and 100: "))
lucky_number = random.randint(1,100)
if response == lucky_number:
print(f"Wow you're right, it is {lucky_number}")
else:
print("Sorry, Try Again")
main()
Reminder:
intended for python3 as i included the format f
also it could be done without the import, just manually insert a number
i'll leave the post mortum to you