1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bearhunter [10]
2 years ago
5

Answer this correct and get brainly

Computers and Technology
2 answers:
Leya [2.2K]2 years ago
5 0

Pseudocode:

import random

fetch user input on a lucky number

insert input into variable - "response"

new variable, random = randint

condition to check wheather random is our response

display results

Python Code:

import random

def main():

response = int(input("Guess my lucky number, its between 1 and 100: "))

lucky_number = random.randint(1,100)

if response == lucky_number:

print(f"Wow you're right, it is {lucky_number}")

else:

print("Sorry, Try Again")

main()

Reminder:

intended for python3 as i included the format f

also it could be done without the import, just manually insert a number

i'll leave the post mortum to you

solniwko [45]2 years ago
4 0

Answer:

Pseudocode:

import random

fetch user input on a lucky number

insert input into variable - "response"

new variable, random = randint

condition to check wheather random is our response

display results

Python Code:

import random

def main():

response = int(input("Guess my lucky number, its between 1 and 100: "))

lucky_number = random.randint(1,100)

if response == lucky_number:

print(f"Wow you're right, it is {lucky_number}")

else:

print("Sorry, Try Again")

main()

Reminder:

intended for python3 as i included the format f

also it could be done without the import, just manually insert a number

Explanation:

You might be interested in
A _ is the acknowledgment of a potential noncomformity, or an opinion regarding an issue that is not covered by a standard
sleet_krkn [62]
Assumption - hope this helped took the test and got 100
5 0
3 years ago
What is the difference between throughput and bandwidth?
masha68 [24]

Answer: Please find below the answer along with explanation.

Explanation:

For  a given communication channel (for instance, a LAN segment using Ethernet ) the Bandwidth refers to the theoretical maximum data rate that the channel can support, for instance, 100 Mbps in a 100Base T network.

The throughput, instead, refers to the actual data rate achieved in a given communications channel, taking into account the different channel impairments.

For instance, in a LAN segment that uses the original Ethernet 802.3 standard (CSMA/CD), a frequent occurrence of collisions can take down the actual data rate from the theoretical 100 Mbps to a very lower figure, i.e., 5 Mbps.

4 0
3 years ago
Create an array of numbers filled by the random number generator. (value = (int)(Math.random() * 100 + 1);) Print the array and
Y_Kistochka [10]

Answer:

Explanation:

the following is the code to run this (JAVA)

MeanStandardDev.java

import java.util.Random;

import java.util.Scanner;

public class MeanStandardDev {

public static void main(String[] args) {

// Declaring variables

int N;

double lower, upper, min, max, mean, stdDev;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

// Getting the input entered by the user

System.out.print(" How many Random Numbers you want to generate :");

N = sc.nextInt();

System.out.print("Enter the Lower Limit in the Range :");

lower = sc.nextDouble();

System.out.print("Enter the Upper Limit in the Range :");

upper = sc.nextDouble();

// Creating Random class object

Random rand = new Random();

double nos[] = new double[N];

// this loop generates and populates 10 random numbers into an array

for (int i = 0; i < nos.length; i++) {

nos[i] = lower + (upper - lower) * rand.nextDouble();

}

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.printf("The Minimum Number is :%.1f\n",min);

System.out.printf("The Maximum Number is :%.1f\n",max);

System.out.printf("The Mean is :%.2f\n",mean);

System.out.printf("The Standard Deviation is :%.2f\n",stdDev);

}

//This method will calculate the standard deviation

private static double calStandardDev(double[] nos, double mean) {

//Declaring local variables

double standard_deviation=0.0,variance=0.0,sum_of_squares=0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for(int i=0;i<nos.length;i++)

{

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares+=Math.pow((nos[i]-mean),2);

}

//calculating the variance of an array

variance=((double)sum_of_squares/(nos.length-1));

//calculating the standard deviation of an array

standard_deviation=Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(double[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static double findMinimum(double[] nos) {

double min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static double findMaximum(double[] nos) {

double max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

the OUTPUT should give;

How many Random Numbers you want to generate :10

Enter the Lower Limit in the Range :1.0

Enter the Upper Limit in the Range :10.0

The Minimum Number is :1.1

The Maximum Number is :9.9

The Mean is :6.30

The Standard Deviation is :2.98

cheers i hope this helps!!!

4 0
3 years ago
______are our thoughts and feelings towards a particular subject
ddd [48]
c....attitudes.....
8 0
3 years ago
You are asked to provide a list of security groups a user is a member of. You write a script to pull the data from Active Direct
Whitepunk [10]

Answer:

I have no clue. I wish I could help though.

Explanation:

Sorry

7 0
3 years ago
Other questions:
  • Suppose that you created an robot that was so advanced it could act independently in very complex situations. It made its own de
    9·1 answer
  • Wich is the last step in conducting a URL search
    14·2 answers
  • There are several methods of updating information and data on a webserver. We must consider who performs those updates upfront w
    9·2 answers
  • A vehicle fails an HC emission test at idle and 2,500 rpm, and the engine has an acceleration stumble. The heated oxygen sensor
    15·1 answer
  • Which are the benefits of leveraging web technologies?
    8·2 answers
  • Which of the following is true of how the Internet has responded to the increasing number of devices now using the network?
    7·1 answer
  • In chapter 3, we discussed syntax and semantics, in general there are two types of grammars for programming languages, regular a
    14·1 answer
  • Discuss two business information systems that are used in two different sectors in a modern economy.
    11·1 answer
  • In which of the following phases of filmmaking would a production team be focused on the
    10·2 answers
  • A company organizes all of its client database in order of the amount of money that the account is worth. When a new account is
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!