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3 years ago

How to work out the equation

Mathematics

1 answer:

sveta [45]3 years ago

8 0

first, distribute -6 to (2b + 1), giving you -12b - 6, and then on the another side of the equation, distribute -2 to (5 + 4b) giving you, -10 - 8b. now we need to put our coefficients on one side so we will add 8b to each side of the equation, giving us -6 = -10 - 8b + 12b, then we will add 10 to both sides of the equation giving us, 10 -6 = -8b +12b, this gives u 4 = 4b. then, you would solve for b, which equals 1.

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The perimeter of a rectangular garden used 86 feet of barbed wire. The length of the garden is 7 feet more than its width. Find

Taya2010 [7]

Answer:

Step-by-step explanation:

perimeter of a rectangle = twice the length plus twice the width

P = 2L + 2W equation 1 P = 86 ft

Given the length is seven feet more than the width

L = W + 7 equation 2

Substitute equation 2 into equation 1

P = 2(W+7) + 2W = 86 ft

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2 years ago

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Answer:

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2 years ago

Is x=5 the solution to the following equation? Show your work with the substitution property

guapka [62]

Answer:

yes

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

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galben [10]

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2 years ago

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Air pressure may be represented as a function of height (in meters) above the

denis-greek [22]

Answer: OPTION C.

Step-by-step explanation:

<h3> The complete exercise is: "Air pressure may be represented as a function of height (in meters) above the surface of the Earth, as shown below:</h3><h3> $P(h) =P_0e^{-0.00012h}$ </h3><h3> In this function $P_o$ is the air pressure at the surface of the earth, and $h$ is the height above the surface of the Earth, measured in meters. At what height will the air pressure equal 50% of the air pressure at the surface of the Earth"</h3><h3></h3>

Given the following function:

$P(h) =P_0e^{-0.00012h}$

In order to calculate at what height the air pressure will be equal 50% of the air pressure at the surface of the Earth, you can follow these steps:

1. You need to substitute $P(h)=0.5P_o$ into the function:

$0.5P_o=P_0e^{-0.00012h}$

2. Finally, you must solve for $h$ .

Remember the following property of logarithms:

$ln(b)^a=a*ln(b)\\\\ln(e)=1$

Then, you get this result:

$0.5P_o=\frac{P_o}{e^{0.00012h}}\\\\(0.5P_o)(e^{0.00012h})=P_o\\\\e^{0.00012h}=\frac{P_o}{0.5P_o}\\\\ln(e)^{0.00012h}=ln(2)\\\\0.00012h*1=ln(2)\\\\h=\frac{ln(2)}{0.00012}\\\\h=5576.2$

7 0

3 years ago