Coordinates for new triangle -
P’(-1,1)
Q’(-3,3)
R’(-3,1)
Answer:
Area of Trapezoid is 39 unit²
Step-by-step explanation:
Given as :
For A Trapezoid
The measure of base side 1 = = 10 unit
The measure of base side 2 = = 16 unit
The height of the Trapezoid = h = 3 unit
Let The Area of Trapezoid = A square unit
<u>Now, From Formula</u>
Area of Trapezoid = × (sum of opposite base) × height
I.e A = × ( + ) × h
Or, A = × (10 unit + 16 unit) × 3 unit
Or, A = × (26 unit) × 3 unit
Or, A = × 78 unit²
Or, A = unit²
I.e A = 39 unit²
So, The Area of Trapezoid = A = 39 unit²
Hence, The Area of Trapezoid is 39 unit² . Answer
Answer:
The answer is C
Step-by-step explanation:
i also use khan
Remember distributive property
a(b+c)=ab+ac
we can ervers it
6(31)+6(4)-6(15)=6(31)+6(4)+6(-15)=6(31+4-15)=6(20)=120
A. The equation is true.
67+33=100
70+30=100
100=100 so yes, the equation is equal.