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3 years ago

Challenge A bag contains pennies, nickels, dimes, and quarters. There are 50 coins in all. Of the

Mathematics

1 answer:

bagirrra123 [75]3 years ago

5 0

Answer:

$6.35

Step-by-step explanation:

Number of pennies = 10% of the 50 coins = .10(50) = 5

Number of dimes = 34% of the 50 coins = .34(50) = 17

Number of nickels = 7 + no. of pennies = 7 + 5 = 12

Number of quarters = 50 - 5 - 17 - 12 = 16

Each penny is 1 cent, each nickel is 5 cents, each dime is 10 cents, and each quarter is 25 cents.

Amount of money in the bag = 5(1) + 17(10) + 12(5) + 16(25) = 5 + 170 + 60 + 400 = 635 cents = $6.35

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Anita is years older than Basilio. Three times Anita's age added to six times Basilio's age is 36. 1. Define the variables 2. Cr

Scilla [17]

Answer :Anita's age = 7 years

Basilio's age = 2.5 years

Step 1. Assign variables to Anita's and Basilio's ages.

Anita's age = A

Basilio's age = B

Step 2. Use the information given to form two equations.

Anita is 4-1/2 years older than Basilio

A = 4.5 + B

Three times Anita's age added to six times Basilio's age is 36

3A + 6B = 36

Step 3. Substitute the value of A from first equation in to the second equation and solve for B

3(4.5 + B) + 6B = 36

13.5 + 3B + 6B = 36

13.5 + 9B = 36

9B = 36 - 13.5

9B = 22.5

B = 22.5/9 = 2.5

Step 4. Find the value of A

A = 4.5 + 2.5 = 7

Answer:

Anita's age = 7 years

Basilio's age = 2.5 years

6 0

3 years ago

Which is bigger .24 or .71

monitta

Answer:

.71

Step-by-step explanation:

7 0

3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

2 years ago

PLEASE ANSWER ASAP I NEED HELP. <br> IT WILL BE MUCH APPRECIATED<br> find the product (x+4)(x-3)

iragen [17]

Answer:

Work shown below!

Step-by-step explanation:

(x + 4)(x - 3) = $x^{2} -3x+4x-12=x^{2} +x-12$

8 0

2 years ago

Read 2 more answers

If you have two horse pastures, one is. 25 feet by 45 feet and the other is 40 feet by 60 feet, what is the perimeter of the two

svp [43]

One field is 25 + 45 + 25 + 45 = 140 feet
Second field is 40 + 60 + 40 + 60 = 200 feet.
Therefore, all together, the two fields are 340 feet in perimeter together

5 0

3 years ago