Since we want just the top 20% applicants and the data is normally distributed, we can use a z-score table to check the z-score that gives this percentage.
The z-score table usually shows the percentage for the values below a certain z-score, but since the whole distribution accounts to 100%, we can do the following.
We want a z* such that:
But, to use a value that is in a z-score table, we do the following:
So, we want a z-score that give a percentage of 80% for the value below it.
Using the z-score table or a z-score calculator, we can see that:
![\begin{gathered} P(zNow that we have the z-score cutoff, we can convert it to the score cutoff by using:[tex]z=\frac{x-\mu}{\sigma}\Longrightarrow x=z\sigma+\mu](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%28zNow%20that%20we%20have%20the%20z-score%20cutoff%2C%20we%20can%20convert%20it%20to%20the%20score%20cutoff%20by%20using%3A%5Btex%5Dz%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5CLongrightarrow%20x%3Dz%5Csigma%2B%5Cmu)
Where z is the z-score we have, μ is the mean and σ is the standard deviation, so:
so, the cutoff score is approximately 72.
Answer:
I'm not sure about the factors, but it's reflected over the x axis if they helps narrow it down
A mixed number and one and two-ninths.
Hope this helps! :D
Answer:
Option c) y=
is correct
The value of y is 3
Step-by-step explanation:
Given equation is
To solve the given equation for y
(converting mixed fraction to normal fraction )
(taking LCM 25 )
(adding the terms )
(now convert fraction into mixed fraction )
Therefore y=
Option c) y= is correct
The value of y is 3
To solve this, we simply need to remember our rules about order of operations. They tell us that first, we should distribute the 2 with the rest of the parentheses.
5-2(x-3)
5-2x+6
Next, we should combine our like-terms.
5-2x+6
11-2x
Seeing as we do not know the value of the variable, the simplest form of the expression is 11-2x.
