I believe the answer is C.
93.53 - 21.41 = 72.12
If you simplify C, its answer becomes equivalent to the answer of the original problem:
(90 - 20) + (3 - 1) + (0.5 - 0.4) + (0.03 - 0.01)
70 + 2 + 0.1 + 0.02
72.12
Answer:
Use the equation
Step-by-step explanation:
y = mx + b
The answer is b because 2-8 is that
Answer:
The answer is B
Step-by-step explanation:
hope this helps
Answer:
The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population proportion <em>P</em> is:

The information provided is:
<em>x</em> = number of students who responded as"yes" = 70
<em>n</em> = sample size = 200
Confidence level = 95%
The formula to compute the sample proportion is:

The R codes for the construction of the 95% confidence interval is:
> x=70
> n=200
> p=x/n
> p
[1] 0.35
> s=sqrt((p*(1-p))/n)
> s
[1] 0.03372684
> E=qnorm(0.975)*s
> lower=p-E
> upper=p+E
> lower
[1] 0.2838966
> upper
[1] 0.4161034
Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).