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Anna007 [38]
2 years ago
10

I need help with #3 ASAP!! Marking brainliest :) Thanks!

Mathematics
1 answer:
Tom [10]2 years ago
7 0

Answer:

the answer is 6x^2

Step-by-step explanation:

goodluck

You might be interested in
Help!!! Will give brainliest to correct answer.....
zlopas [31]
I believe the answer is C.

93.53 - 21.41 = 72.12

If you simplify C, its answer becomes equivalent to the answer of the original problem:

(90 - 20) + (3 - 1) + (0.5 - 0.4) + (0.03 - 0.01)

70 + 2 + 0.1 + 0.02

72.12
7 0
3 years ago
A line with a slope of 1/4 passes through the point (5, 6). What is its equation in point-slope
diamong [38]

Answer:

Use the equation

Step-by-step explanation:

y = mx + b

4 0
2 years ago
If the graph of function g is 6 units below the graph of function f, which could be function g?
Olegator [25]
The answer is b because 2-8 is that
4 0
3 years ago
2
emmasim [6.3K]

Answer:

The answer is B

Step-by-step explanation:

hope this helps

5 0
2 years ago
A survey of 200 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take
Lina20 [59]

Answer:

The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population proportion <em>P</em> is:

CI=p\pm z_{\alpha/2}\sqrt{\frac{p(1- p)}{n}}

The information provided is:

<em>x</em> = number of students who responded as"yes" = 70

<em>n</em> = sample size = 200

Confidence level = 95%

The formula to compute the sample proportion is:

p=\frac{x}{n}

The R codes for the construction of the 95% confidence interval is:

> x=70

> n=200

> p=x/n

> p

[1] 0.35

> s=sqrt((p*(1-p))/n)

> s

[1] 0.03372684

> E=qnorm(0.975)*s

> lower=p-E

> upper=p+E

> lower

[1] 0.2838966

> upper

[1] 0.4161034

Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).

7 0
3 years ago
Read 2 more answers
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