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Alexxandr [17]
4 years ago
5

A certain motorcycle manufacturer has been building motorcycles for 98 years. Over that period, production has increased steadil

y at an annual rate of 5%, so that the production rate, in motorcycles/year, after t years was
r(t)=A⋅1.05^t


where A is a constant representing the initial production rate. What fraction of their total production was built during the last 13 years? Your answer should be a number between 0 and 1.
Mathematics
1 answer:
Reika [66]4 years ago
5 0

Answer: The fraction would be 0.53.

Step-by-step explanation:

Since we have given that

r(t)=A.(1.05)^t

where, A is the constant initial production rate

t is the time.

For 98 years, the production rate in motorcycles per year would be

r(98)=A.(1.05)^{98}\\\\r(98)=A.119.27

For 13 years, the production rate in motorcycles per year would be

r(98-13)=r(85)=A.(1.05)^{85}\\\\r(85)=A.63.25

So, the fraction of their total production was built during the last 13 years would be

\dfrac{r(85)}{r(98)}=\dfrac{63.25}{119.27}=0.53

Hence, the fraction would be 0.53.

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13) As they’ve given the zeros, you can use those to create factors. Since the zeros are x=-1, x=-3, and x=4, by making the right side 0 in each equation, you get the factors (x+1), (x+3), and (x-4). Then, you can multiply those factors using box method or FOIL or whichever method you prefer. By multiplying (x+1) and (x+3), I got x^2+4x+3. Then, I multiplied that by (x-4) to get x^3-13x-12, which is your final answer.

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