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4 years ago

What is the nearest thousand place for 3,429

1 answer:

muminat4 years ago

8 0

If the place to the right of where you are rounding is 5 or higher, you have to round up. If it is 4 or lower, you have to round down. In the hundreds place, there is a 4. That's lower than 5 meaning that you round down/stay. So, the nearest thousands place is 3,000.

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Below is a drawing of a wall that is to be covered with either wallpaper or paint. The wall is 8 ft. high and

Snowcat [4.5K]

84 sq. ft of the wall has to be covered with paint or wallpaper.

Step-by-step explanation:

Step 1: Find the area of wallpaper to be covered by calculating the area of the wall and subtracting the areas of the window, mirror and fireplace from it. All are rectangular in shape with are given by A = length × width

Area of the wall = 8 × 16 = 128 ft²

Area of the window = 18/12 × 14 = 1.5 × 14 = 21 ft² (since 1 ft = 12 in)

Area of the fireplace = 5 × 3 = 15 ft²

Area of the mirror = 4 × 2 = 8 ft²

Step 2: Calculate the area to be painted or covered with wallpaper

Area of the wall to be covered with paint or wallpaper = 128 - (21 + 15 + 8)

= 128 - 44

= 84 ft²

5 0

4 years ago

Read 2 more answers

An account is opened with $7,595.96 with a rate of 2%

olganol [36]

The answer is right above me yw lol

3 0

3 years ago

Find all the solutions in there interval (0,2pi) for cos5x=-1/2

oee [108]

Answer:

$\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}$

Step-by-step explanation:

Solving trigonometric equations.

We are given a condition and we must find all angles who meet it in the provided interval. Our equation is

$cos5x=-\frac{1}{2}$

Solving for 5x:

$5x=\frac{2\pi}{3}+2n\pi$

$5x=\frac{4\pi}{3}+2n\pi$

The values for x will be

$x=\frac{\frac{2\pi}{3}+2n\pi}{5}$

$x=\frac{\frac{4\pi}{3}+2n\pi}{5}$

To find all the solutions, we'll give n values of 0, 1, 2,... until x stops belonging to the interval $(0,2\pi)$

For n=0

$x=\frac{\frac{2\pi}{3}}{5}=\frac{2\pi}{15}$

$x=\frac{\frac{4\pi}{3}}{5}=\frac{4\pi}{15}$

For n=1

$x=\frac{\frac{2\pi}{3}+2\pi}{5}=\frac{8\pi}{15}$

$x=\frac{\frac{4\pi}{3}+2\pi}{5}=\frac{2\pi}{3}$

For n=2

$x=\frac{\frac{2\pi}{3}+4\pi}{5}=\frac{14\pi}{15}$

$x=\frac{\frac{4\pi}{3}+4\pi}{5}=\frac{16\pi}{15}$

For n=3

$x=\frac{\frac{2\pi}{3}+6\pi}{5}=\frac{4\pi}{3}$

$x=\frac{\frac{4\pi}{3}+6\pi}{5}=\frac{22\pi}{15}$

For n=4

$x=\frac{\frac{2\pi}{3}+8\pi}{5}=\frac{26\pi}{15}$

$x=\frac{\frac{4\pi}{3}+8\pi}{5}=\frac{28\pi}{15}$

For n=5 we would find values such as

$x=\frac{\frac{2\pi}{3}+10\pi}{5}=\frac{32\pi}{15}$

$x=\frac{\frac{4\pi}{3}+10\pi}{5}=\frac{34\pi}{15}$

which don't lie in the interval $(0,2\pi)$

The whole set of results is

$\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}$

6 0

3 years ago

Describe how you know if an equation has INFINITE solutions. Give some examples of an equation that has infinite solutions,

MArishka [77]

Answer:

When a problem has infinite solutions, you'll end up with a statement that's true no matter what. For example: 3=3 This is true because we know 3 equals 3, and there's no variable in sight. Therefore we can conclude that the problem has infinite solutions. You can solve this as you would any other question.

Step-by-step explanation:

Hope this helped.

5 0

3 years ago

24 cups in how many quarts

alisha [4.7K]

1 Quart = 4 Cups
So, 6 Quarts = 24 Cups

4 0

3 years ago

Read 2 more answers