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babymother [125]
3 years ago
13

A study on students drinking habits asks a random sample of 60 male UF students how many alcoholic beverages they have consumed

in the past week. The sample reveals an average of 5.84 alcoholic drinks, with a standard deviation of 4.98. Construct a 95% confidence interval for the true average number of alcoholic drinks all UF male students have in a one week period.
A. (4.78, 6.90)

B. (0, 15.60)

C.(4.58, 7.10)

D. (-3.92, 15.60)
Mathematics
1 answer:
Alex17521 [72]3 years ago
8 0

Answer:

A. (4.78, 6.90)

Step-by-step explanation:

Using the following formulas the lower and upper limits of the Interval are calculated

Lower limit = mean - (standard deviation /√sample size)* Zr

Upper limit = mean + (standard deviation /√sample size)* Zr

Zr depends on confidence interval  and can be found in a z table

Zr for 90% = 1.645

then

Lower limit = 5.84 - (4.98 /√60)* 1.645 = 4.78

Upper limit = 5.84 + (4.98 /√60)* 1.645 = 6.90

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Answer:

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Step-by-step explanation:

Let a be the number of bags with 8 onions and let b be the number of bags with 3 onions. We have the following system of equations:

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Subtracting b from both sides of the first equation, we get a=7-b. Substitute this into the second equation:

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Thus, the chef got 4 8-onion bags and 3 3-onion bags.

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Answer:

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