We know that
[volume of a <span>cylindrical paint can 1]=[area of the base]*h
so
</span>[area of the base]*h=1 gallon
if <span>the height is doubled
</span>[volume of a cylindrical paint can 2]=[area of the base]*(2*h)
[volume of a cylindrical paint can 2]=2*{[area of the base]*h)}
[volume of a cylindrical paint can 2]=2*[volume of a cylindrical paint can 1]
[volume of a cylindrical paint can 2]=2*[1 gallon]-----> 2 gallons
the answer is
<span>the capacity of the lager one is 2 gallons</span>
Answer: the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
Step-by-step explanation:
Given data;
lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min
hence, height = 1 / ( 52.0 - 50.0) = 1 / 2
now the probability that the class length is between 50.8 and 51 min = ?
P( 50.8 < X < 51 ) = base × height
= ( 51 - 50.8) × 1/2
= 0.2 × 0.5
= 0.1 ≈ 10%
therefore the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
The volume of the cone is: A. 213 ft³.
<h3>Volume of a Cylinder and a Cone</h3>
- Volume of cylinder = πr²h.
- Volume of cone = ⅓πr²h.
Given:
radius and height of both the cylinder and the cone are equal.
Volume of Cylinder = 639 ft³
Therefore:
πr²h = ⅓πr²h
This means that volume of cone would be ⅓ of the volume of the cylinder.
Volume of cone = ⅓(639) = 213 ft³
Therefore, the volume of the cone is: A. 213 ft³.
Learn more about volume of cone on:
brainly.com/question/13677400
Answer:
2^3×3^2
and yh
Step-by-step explanation:
2×2×2×3×3
