You didn't ask a question but its called a period
F(x) = 2x² - 8x - 10.
This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:
a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex
b) for x = 2, f(x) = f(2) = - 18 (component of y of the vertex)
c) VERTEX(2, - 18)
d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144
The probability of loss is 0.2 because they must add up to 1.
Answer:
y=x,y=12x+1
y=4x+4,y=6x
y=x+1,y=x+4
Step-by-step explanation:
