Answer:
The velocity of the nickel just before it hits the ground is approximately 49.3 m/s
Explanation:
In order to calculate the velocity of the nickel just before it hits the ground, we recall the kinematic equation of motion, v² = u² + 2·g·h, where the variables of the equation are defined as follows;
v = The velocity of the nickel just before it hits the ground after it is pushed off the observation deck
u = The initial velocity of the nickel just before it is pushed off the observation deck = 0 m/s
g = The acceleration due to gravity = 9.8 m/s²
h = The height from which he nickel is pushed off the edge = 124 m
Substituting the given values and the constant, "g", we have;
v² = 0² + 2 × 9.8 × 124 = 2,430.4
v = √2,430.4
Using a graphing calculator, we have;
v = √2,430.4 = 14·√(62/5) ≈ 49.3
The velocity of the nickel just before it hits the ground = v ≈ 49.3 m/s.
