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3 years ago

5

Which cannot be separated into simpler substances?

2 answers:

marin [14]3 years ago

6 0

Answer:

An element is a pure substance that cannot be separated into simpler substances by chemical or physical means. There are about 117 elements.

Explanation:

Vikentia [17]3 years ago

6 0

Answer:

A pure substance

Explanation:

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How to find the acceleration of a system?

natta225 [31]

The acceleration can be found by:
$\frac{v}{t}$
Where v= velocity and t= time
or
$a = \frac{f}{m}$

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3 years ago

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What is the<br> power of a light<br> bulb with 8V and<br> a current of 2A?

astra-53 [7]

Answer:

16 Watts

Explanation:

P = VI, where V is the voltage and I is the current (of the lightbulb)

V = 8 volts, I = 2 amps

P = 8 * 2 = 16 Watts

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3 years ago

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Discuss how a photon (aka the light particle) can be affected by gravity despite being massless.

Over [174]

Explanation:

Light is clearly affected by gravity, just think about a black hole, but light supposedly has no mass and gravity only affects objects with mass. On the other hand, if light does have mass then doesn't mass become infinitely larger the closer to the speed of light an object travels.

4 0

3 years ago

There are 640 acres in a square mile. how many square meters are there in 7.80 acres.

lukranit [14]

Answer:

On 7.8 acres there are 31565.3 square meters

7.8 acres = 31565.3 m²

Explanation:

Conceptual analysis

Acre, square mile and square meter are area units, so their equivalences are in square units.

Known data

1 (mi)² = 640 acres

1 mi = 1609.34 m

Problem development

We know that 1 mile = 1609.34m, then: (1 mile)² = (1609.34m)²=(1609.34)²m²

We apply the known conversion factors to calculate the square meters (X) in 7.8 acres:

$X=7.8 acres *\frac{(1 mi)^{2} }{640 acres} * \frac{(1609.34)^{2}m^{2} }{(1 mi)^{2} }$

We eliminate acres and square miles (mi²) because they are in the numerator and denominator, so the answer is in square meters (m²)

X=31565.3 m²

On 7.8 acres there are 31565.3 square meters

7.8 acres = 31565.3 m²

8 0

3 years ago

A mass of 6 kg with initial velocity 16 m/s travels through a wind tunnel that exerts a constant force 8 N for a distance 1.6 m.

strojnjashka [21]

Answer:

$D=99.4665307m \approx 99.5m$

Explanation:

From the question we are told that

Mass $m=6kg$

Velocity of mass $V_m=16$

Force of Tunnel $F_t=8N$

Length of Tunnel $L_t=1.6$

Height of frictional incline $H_i=2.9$

Angle of inclination $\angle =16 \textdegree$

Acceleration due to gravity $g=9.8m/s^2$

First Frictional surface has a coeﬃcient $\alpha_1 =0.21\ for\ d_c=1$

Second Frictional surface has a coeﬃcient $\alpha _2=0.1$

Generally the initial Kinetic energy is mathematically given by

$K.E=\frac{1}{2}mv^2$

$K.E=\frac{1}{2}(6)(16)^2$

$K.E=768$

Generally the work done by the Tunnel is mathematically given as

$w_t=F_t*d_t$

$w_t=8*1.6$

$w_t=12.8J$

Therefore

$Total energy\ E_t=Initial\ kinetic energy\ K.E*Work done\ by\ tunnel\ W_t$

$E_t=K.E+E_t\\E_t=768J+12.8J$

$E_t=780.8J$

Generally the energy lost while climbing is mathematically given as

$E_c=mgh$

$E_c=(6)(9.8)(2.9)$

$E_c=170.52J$

Generally the energy lost to friction is mathematically given as

$E_f=\alpha *m*g*cos\textdegree*d_c$

$E_f=0.21*6*9.8*cos16*1$

$E_f=11.86965942 \approx 12J$

Generally the energy left in the form of mass $Em$ is mathematically given as

$E_m=E_t+E_c+E_f$

$E_m=(768J)-(170.52)-(12)$

$E_m=585.48J$

Since

$E_m=\alpha_2*g*m*d$

Therefore

It slide along the second frictional region

$D=\frac{585.46}{0.1*9.81*6}$

$D=99.4665307m \approx 99.5m$

6 0

3 years ago