A. The Dawes limit tells
us that the resolving power is equal to 11.6 / d, where d is the diameter of
the eye’s pupil in units of centimeters. The eye's pupil can dialate to approximately
7 mm, or 0.7 cm. So 11.6 / .7 = 16.5 arc seconds, or about a quarter arc
minute ~ 17 arc seconds<span>
Although, the standard answer for what people can really see
is about 1 arc minute.
</span>
<span>
B. It is considered as linear, so given a 10 meter telescope
(10,000 mm): </span>
10000 / 7 = 1428 times
better for the 10 meter scope ~ 1400 times better (in 2 significant figures)
<span>
<span>C. For a 7 cm interferometer, that is just similar to a 7 cm
scope. Therefore we would expect </span></span>
<span><span>11.6 / 7 = 1.65 arc seconds ~ 1.7 arc seconds</span></span>
<span><span>T</span></span>his value is what
we typically can get from a 7 cm scope.
Total Current = 2 Amps
Req total = 60 ohms
Current on EF mesh = 1/3 Amp
Current on 24 ohms resistor = 1/6 Amp
Voltage on the 40ohms resistor is lefting.
Answer : The change in enthalpy of the reaction is, -310 kJ
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given main reaction is,

The intermediate balanced chemical reaction will be,
(1)

(2)

(3)

Now we will reverse the reaction 1 and multiply reaction 1 by 2, reaction 2 by 2 and reaction 3 by 3 then adding all the equations, we get :
(1)

(2)

(3)

The expression for enthalpy of formation of
will be,



Therefore, the change in enthalpy of the reaction is, -310 kJ
The people are using a lot of electricity blow drying to many peoples hair so i would make a schedule so it dosent get to busy with costumers
Answer:
Explanation:
Stress is the force applied to a rock and may cause deformation. The three main types of stress are typical of the three types of plate boundaries: compression at convergent boundaries, tension at divergent boundaries, and shear at transform boundaries.