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Andreyy89
3 years ago
10

A 3.5 x 10-6 C charge is located 0.28 m from a 2.8 x 10-6 C charge. What is the magnitude of the force being exerted on the smal

ler charge, to the nearest tenth of a Newton?
Physics
1 answer:
Margarita [4]3 years ago
7 0
The electrostatic force between two charges is given by Coulomb's law:
F=k_e  \frac{q_1 q_2}{r^2}
where
ke is the Coulomb's constant
q1 is the first charge
q2 is the second charge
r is the separation between the two charges

By substituting the data of the problem into the equation, we can find the magnitude of the force between the two charges:
F=(8.99 \cdot 10^{9} Nm^2C^{-2} ) \frac{(3.5 \cdot 10^{-6} N/C)(2.8 \cdot 10^{-6}N/C)}{(0.28m)^2}=1.2 N
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Andre45 [30]

Answer:

The speed of the stone before it hit the river 3.00 sec later. Let v is the velocity at that instant is 45 m/s.

Explanation:

Given that, a child threw a stone straight down off a high bridge.

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We need to find the speed of the stone before it hit the river 3.00 sec later. Let v is the velocity at that instant. When it come down, it is moving under the action of gravity. Using equation of motion as :

v=u+gt\\\\v=15+10\times 3\\\\v=45\ m/s

So, the speed of the stone before it hit the river 3.00 sec later. Let v is the velocity at that instant is 45 m/s.

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3 years ago
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Mandarinka [93]

Answer:

4.9 x 10⁻⁴N

Explanation:

Given parameters:

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Unknown:

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2 years ago
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n200080 [17]
To calculate the force of impact F, first lets calculate the acceleration a of the ball: 

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F=m*a= 0.2*40 = 8 N

So the impact force is F= 8 N.
5 0
3 years ago
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