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3 years ago

What are the period and amplitude of the function?

Mathematics

1 answer:

Marta_Voda [28]3 years ago

7 0

Answer: it’s a

Step-by-step explanation:

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We wish to give a 90% confidence interval for the mean value of a normally distributed random variable. We obtain a simple rando

coldgirl [10]

Answer: $(9.27025,\ 11.12975)$

Step-by-step explanation:

Given : Sample size : n= 9

Degree of freedom = df =n-1 =8

Sample mean : $\overline{x}=10.2$

sample standard deviation : $s= 1.5$

Significance level ; $\alpha= 1-0.90=0.10$

Since population standard deviation is not given , so we use t- test.

Using t-distribution table , we have

Critical value = $t_{\alpha/2, df}=t_{0.05 , 8}=1.8595$

Confidence interval for the population mean :

$\overline{x}\pm t_{\alpha/2, df}\dfrac{s}{\sqrt{n}}$

90% confidence interval for the mean value will be :

$10.2\pm (1.8595)\dfrac{1.5}{\sqrt{9}}$

$10.2\pm (1.8595)\dfrac{1.5}{3}$

$10.2\pm (1.8595)(0.5)$

$10.2\pm (0.92975)$

$(10.2-0.92975,\ 10.2+0.92975)$

$(9.27025,\ 11.12975)$

Hence, the 90% confidence interval for the mean value= $(9.27025,\ 11.12975)$

6 0

3 years ago

Someone help me I will mark you the brainiest

love history [14]

Answer:

i think the answer b its pretty close

Step-by-step explanation:

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3 years ago

Please help. will mark brainliest (part two) lol

Archy [21]

Is going to be 32 ft

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3 years ago

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Please help i’ll do anything and give the brain thing :((

ASHA 777 [7]

Answer:

add me on snap kharding1805 and I will add you back

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2 years ago

Anybody know this? Ive been struggling with it for a bit now..

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2 years ago