The value of x is 8 when y = 12 if variables x and y have proportional relationship.
According to the given question.
Variables y and x have proportional relationship.
⇒ y ∝ x
Let k be the constant of proportionality.
⇒ y = kx
Also, it is given that
y = 21 when x = 14
Substitute the value of y = 21 and x = 14 in y = kx to find the value of k.
21 = k(14)
⇒ k = 21/14
⇒ k = 3/2
Therefore, the value of x when y = 12
y = kx
⇒ 12 = (3/2)x
⇒ 12 × 2 = 3x
⇒ 24 = 3x
⇒ x = 24/3
⇒ x = 8
Hence, the value of x is 8 when y = 12.
Find out more information about proportional relationship here:
brainly.com/question/12917806
#SPJ4
Answer: x = 1 and -16
Explanation:
(4x^32 - 14x^16 + 2x^3 - 8)/x - 1
x - 1 = 0
x = 1
f(x) = 4x^32 - 14x^16 + 2x^3 - 8
f(1) = 4(1)^32 - 14(1)^16 + 2(1)^3 - 8
f(1) = 4 - 14 + 2 - 8
f(1) = -10 - 6
f(1) = -16
Therefore, the remainder is -16
Answer:
9.008 < 9.08
Step-by-step explanation:
9.08 is greater because you compare the number 9 and 9 are the same, 0 and 0 still the same, but then 0 and 8 you know eight is greater. was this helpful enough
Rose petal with 5 petals
Domain: all real numbers
Range: [-2,2]
Symmetric about the x-axis
Continuous
Bounded
Maximum r-value: 2
No asymptotes
