Question

The nth term of a sequence is 2n2 + 1 The nth term of a different sequence is 65 - 2n2. Show that there is only 1 number that is in both of these sequences

Answer 1

Answer:

The only common term is 33.

Step-by-step explanation:

We are given the following in the question:

Sequence 1:

$n^{th}\text{ term: } 2n^2 + 1$

Sequence 2:

$n^{th}\text{ term: } 65 - 2n^2$

Equating the two terms, we get,

$2n^2 + 1 = 65 - 2n^2\\4n^2 = 64\\\\n^2 = \dfrac{64}{4}\\\\n^2 = 16\\n = \pm 4$

Since, n cannot take a negative value, we get n = 4.

Thus, there is only 1 common term both the series have for n = 4.

Common term:

$2(4)^2+ 1 - 65-2(4)^2 = 33$

Thus, the only common term is 33.