Given:
Consider the below figure attached with this question.
In circle A below, chord BC and diameter DAE intersect at F.
The arc CD = 46° and arc BE = 78°.
To find:
The measure of angle BFE.
Solution:
According to intersecting chords theorem, if two chords intersect inside the circle then the angle on the intersection is the average of intercepted arcs.
Using intersecting chords theorem, we get
Therefore, the measure of angle BFE is 62°.
To find the transformation, compare the function to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x-axis or y-axis, and if there is a vertical stretch.
Vertical compression
Answer:
Step-by-step explanation:
A(11, –2, –6) and B(–3, 7, –5) are located away from the origin (0,0,0), the points from the origin to this points is expressed as OB - OA where;
OB is the distance from the origin to the point B
OA is the distance from the origin to the point A
Using the formula for calculating distance between two points
OA = √(z2-z1)²+(y2-y1)²+(x2-x1)²
OA = √(-6-0)²+(-2-0)²+(11-0)²
OA = √(-6)²+(-2)²+(11)²
OA = √36+4+121
OA = √161
OA = 12.688
Similarly;
OB = √(-5-0)²+(7-0)²+(-3-0)²
OA = √(-5)²+(7)²+(-3)²
OA = √25+49+9
OA = √83
OA = 9.110
Distance from the origin to the points = 12.688 - 9.110 = 3.577
Distance from the origin to the points ≈ 3.6 (to the nearest tenth)
Lol it would be too hard to explain by typing but here you go,, hopefully u can read my writing
Answer:
Width = 152 cm
Length = 3040 cm
Step-by-step explanation:
We are given that the length of one flat square shaped slab is 231.04 cm².
Since it is a square, dimension of one side of the flat slab = √231.04 = 15.2 cm
Since there are ten flat slabs, with of the 10 slabs = 10 × 15.2 = 152 cm
Now these slabs are placed across 200 rows to form a walkway.
Thus, length = 200 × 15.2 = 3040 cm
