Because specular reflection occurs with a mirror, while diffuse reflection occurs with aluminium or iron plate
Explanation:
Reflection is a phenomenon typical of waves (such as light wave), that occurs when a wave bounces off the surface of a certain material, going back into the original medium at a certain angle, without changing speed, frequency or wavelength.
The direction of the reflected ray is given by the law of reflection, which states that:
- The incoming ray, the reflected ray and the normal to the surface all lie on the same plane
- The angle of incidence is equal to the angle of reflection
Depending on the type of surface, two different types of reflection can occur:
- Specular reflection: this occurs when the surface is perfectly smooth. In such a case, all the incoming rays of light hit the surface with same angle of incidence, therefore they are reflected at the same angle. This means that a perfect and clear image of the original object can be formed: this is the case of a mirror.
- Diffuse reflection: when the surface is not smooth, the imperfections on the surface are such that the incoming rays of light hit the surface at different angles of incidence. As a result, the rays are reflected at different angles to each other, and therefore no clear image of the object is produced. This is the case of aluminium or iron plate.
Learn more about reflection and other wave phenomena:
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Answer:
9.81N
Explanation:
the force of attraction is given by
F=<u>GmM</u><u>/</u><u>R²</u><u> </u>
where m is mass of the body
M is mass of the earth
R is radius of the earth
G is the universal gravitational constant(6.67x10-¹¹)
hence we substitute the values in the formula.
<em> </em><em>you</em><em> </em><em>can</em><em> </em><em>ask</em><em> </em><em>questions</em>
Answer
given,
constant speed of cart on right side = 2 m/s
diameter of nozzle = 50 mm = 0.05 m
discharge flow through nozzle = 0.04 m³
One-fourth of the discharge flows down the incline
three-fourths flows up the incline
Power = ?
Normal force i.e. Fn acting on the cart
v is the velocity of jet
Q = A V
v = 20.37 m/s
u be the speed of cart assuming it to be u = 2 m/s
angle angle of inclination be 60°
now,
F n = 2295 N
now force along x direction
Power of the cart
P = F x v
P = 1987.52 x 20.37
P = 40485 watt
P = 40.5 kW
Complete question:
A 0.50 kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the acceleration of the frog is 4.0 meters per second^2. Calculate The magnitude of the net force exerted on the frog as it leaps.
Answer:
2.0N
Explanation:
Given that,
Mass, m of the frog = 0.5 kg
The acceleration of the frog = 4.0 m/s².
We have been asked To find,
The magnitude of the net force exerted on the frog as it leaps.
So
We calculate this using the formula below :
F = ma
When we insert the values into the formula, we have:
F = 0.5 kg × 4 m/s²
F = 2.0 N
Therefore, the magnitude of net force is 2.0 N.
This would be called a Joule. The formula for energy is <span>P.E. = mgh (otherwise known as the gravitational force formula, which is energy.) M is the mass in kilograms, and G is the acceleration due to gravity, which is actually (9.</span>8 m / s2<span> at the surface of the earth.) I hope this helps! ~Mia</span>
