Answer:
![\dfrac{q_1}{q_2}=2\left(\dfrac{2}{5}\right )^{3/2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bq_1%7D%7Bq_2%7D%3D2%5Cleft%28%5Cdfrac%7B2%7D%7B5%7D%5Cright%20%29%5E%7B3%2F2%7D)
Explanation:
Given that
Charge on ring 1 is q1 and radius is R.
Charge on ring 2 is q2 and radius is R.
Distance ,d= 3 R
So the total electric field at point P is given as follows
Given that distance from ring 1 is R
![\dfrac{1}{4\pi\epsilon _o}\dfrac{q_1R}{(R^2+R^2)^{3/2}}-\dfrac{1}{4\pi\epsilon _o}\dfrac{q_2(d-R)}{(R^2+(d-R)^2)^{3/2}}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B4%5Cpi%5Cepsilon%20_o%7D%5Cdfrac%7Bq_1R%7D%7B%28R%5E2%2BR%5E2%29%5E%7B3%2F2%7D%7D-%5Cdfrac%7B1%7D%7B4%5Cpi%5Cepsilon%20_o%7D%5Cdfrac%7Bq_2%28d-R%29%7D%7B%28R%5E2%2B%28d-R%29%5E2%29%5E%7B3%2F2%7D%7D%3D0)
![\dfrac{1}{4\pi\epsilon _o}\dfrac{q_1R}{(R^2+R^2)^{3/2}}-\dfrac{1}{4\pi\epsilon _o}\dfrac{q_2(3R-R)}{(R^2+4R^2)^{3/2}}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B4%5Cpi%5Cepsilon%20_o%7D%5Cdfrac%7Bq_1R%7D%7B%28R%5E2%2BR%5E2%29%5E%7B3%2F2%7D%7D-%5Cdfrac%7B1%7D%7B4%5Cpi%5Cepsilon%20_o%7D%5Cdfrac%7Bq_2%283R-R%29%7D%7B%28R%5E2%2B4R%5E2%29%5E%7B3%2F2%7D%7D%3D0)
![\dfrac{q_1R}{(2R^2)^{3/2}}-\dfrac{q_2(2R)}{(5R^2)^{3/2}}=0](https://tex.z-dn.net/?f=%5Cdfrac%7Bq_1R%7D%7B%282R%5E2%29%5E%7B3%2F2%7D%7D-%5Cdfrac%7Bq_2%282R%29%7D%7B%285R%5E2%29%5E%7B3%2F2%7D%7D%3D0)
![\dfrac{q_1}{q_2}=2\left(\dfrac{2}{5}\right )^{3/2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bq_1%7D%7Bq_2%7D%3D2%5Cleft%28%5Cdfrac%7B2%7D%7B5%7D%5Cright%20%29%5E%7B3%2F2%7D)
Answer:
300kgm/s
Explanation:
Given parameters:
Mass of TV = 30kg
Height of building = 5m
Maximum speed = 10m/s
Unknown:
Momentum before it hits the ground = ?
Solution:
Momentum is the quantity of motion a body possess or contains. It is expressed as;
Momentum = mass x velocity
Insert the parameters and solve;
Momentum = 30 x 10
Momentum = 300kgm/s
<span>There are several main pieces of evidence that support the Big Bang theory.
One is the fact that the universe is expanding, proven with something
called red shift. The second is something called cosmic microwave
background radiation. The third is the abundance of different elements
in the universe.
</span>
Your potential energy at the top of the hill was (mass) x (gravity) x (height) .
Your kinetic energy at the bottom of the hill is (1/2) x (mass) x (speed)² .
If there was no loss of energy on the way down, then your kinetic energy
at the bottom will be equal to your potential energy at the top.
(1/2) x (mass) x (speed)² = (mass) x (gravity) x (height)
Divide each side by 'mass' :
(1/2) x (speed)² = (gravity) x (height) . . . The answer we get
will be the same for every skater, fat or skinny, heavy or light.
The skater's mass doesn't appear in the equation any more.
Multiply each side by 2 :
(speed)² = 2 x (gravity) x (height)
Take the square root of each side:
<u>Speed at the bottom = square root of(2 x gravity x height of the hill)</u>
We could go one step further, since we know the acceleration of gravity on Earth:
Speed at the bottom = 4.43 x square root of (height of the hill)
This is interesting, because it says that a hill twice as high won't give you
twice the speed at the bottom. The final speed is only proportional to the
<em>square root </em>of the height, so in order to double your speed, you need to
find a hill that's <em>4 times</em> as high.
Answer:
Isaac Newton came up with the 3 Laws of Motion