Answer:
Belong to the same group.
Explanation:
Different elements are most likely to react in similar ways when they belong to the same group.
This is because the elements in the same group always have similar number of valence electrons which implies that they all have the same number of electrons in their outermost shell. For example,barium (Ba), beryllium (Be), calcium (Ca), magnesium (Mg), radium (Ra), strontium (Sr) all have 2 electrons in their outermost shell and thus they belong to group 2 of elements which are known as Alkaline earth metals and they all tend to react in the same manner with other substances
Answer:
1. a = -10 m/s²
2. a = 1.8 × 10³ km/h²; s = 0.31 km
Explanation:
1.
Given:
Initial speed (u): 30 m/s
Final speed (v): 0 m/s (rest)
Time elapsed (t): 3.0 s
Asked:
Acceleration (a)
Solution:
We will use the following expression.
a = (v-u)/t = (0 m/s - 30 m/s)/3.0 s = -10 m/s²
Final Answer:
a = -10 m/s²
2.
Given:
Initial speed (u): 50 km/h
Final speed (v): 60 km/h
Time elapsed (t): 20 s
Asked:
(a) Acceleration (a)
(b) Distance traveled (s)
Solution:
(a) First, we will convert the time to hours.
20 s × 1 h/3600 s = 0.0056 h
Then, we will use the following expression.
a = (v-u)/t = (60 km/h - 50 km/h)/0.0056 h = 1.8 × 10³ km/h²
(b) We will use the following expression.
s = u × t + 1/2 × a × t²
s = 50 km/h × 0.0056 h + 1/2 × 1.8 × 10³ km/h² × (0.0056 h)² = 0.31 km
Final Answer:
a = 1.8 × 10³ km/h²
s = 0.31 km
For the pH of a solution prepared by dissolving 0. 350 mol of solid methylamine hydrochloride, the pH is mathematically given as
pH = 11.14
<h3>What is the pH value of a solution prepared by dissolving 0. 350 mol ?</h3>
Generally, the equation for the pKb is mathematically given as
pKb = -logKb
Therefore
pKb of CH3NH2 = -log(4.40×10-4)
pKb of CH3NH2= 3.36
Hence
pKa= 14 - pKb
pKa= 14 - 3.36
pKa= 10.64
In conclusion, using
pH = pKa + log([A-]/[HA])
pH = 10.64 + log(1.10M/0.350M)
pH = 11.14
Read more about pH value
brainly.com/question/1584537
I believe the answer to this is An increase in temperature of nearby stream
(3) the forward reaction rate is equal to the reverse reaction rate
hope this helps!