Answer:
2Fe⁺³ + Sn₂ → 2Fe⁺² + 2Sn⁺²
Explanation:
A redox reaction occurs between a compound that loses electrons and others that gain an electron. The first is being oxidized, and the other is being reduced.
In this situation, in the compound Fe₂O₃, the iron, has an oxidation number equal to +3, so it's Fe⁺³, and it will gain 1 electron to become Fe⁺². Because it was first dissolved in HCl, we must use the ion at the equation. The other compound Sn₂ will be oxidized to Sn⁺², so it will need to lose 2 electrons.
So, it will be necessary 2 Fe⁺³ for this reaction happen:
2Fe⁺³ + Sn₂ → 2Fe⁺² + 2Sn⁺²
Answer:
The total pressure of the gas mixture = 2.76 atm
Note: The question is not complete. The complete question is as follow:
If 43.1 g of O2 and 6.8 g of CO2 are placed in a 13.7 L container at 34 degree Celsius , what is the pressure of the mixture of gases?
Explanation:
Mass of O₂ gas = 43.1 g, molar mass of O₂ gas = 32.0 g/mol
Number of moles of O₂ gas = 43.1/32.0 = 1.347 moles
Mass of CO₂ gas = 6.8 g, molar mass of CO₂ gas = 44.0 g
Number of moles of CO₂ gas = 6.8/44 = 0.155 moles
Total number of moles of gas mixture, n = (1.347 + 0.155) = 1.502 moles
Volume of gas mixture, V = 13.7 L
Temperature of gas mixture, T = 34 °C = (273.15 + 34) K = 307.15 K
Pressure of gas mixture = ?
Molar gas constant, R = 0.0821 liter·atm/mol·K.
Using the ideal gas equation: PV =nRT
P = nRT/V
P = (1.502 × 0.0821 × 307.15) / 13.7
P = 2.76 atm
Therefore, the total pressure of the gas mixture = 2.76 atm
Answer:
The correct option is;
d 4400
Explanation:
The given parameters are;
The mass of the ice = 55 g
The Heat of Fusion = 80 cal/g
The Heat of Vaporization = 540 cal/g
The specific heat capacity of water = 1 cal/g
The heat required to melt a given mass of ice = The Heat of Fusion × The mass of the ice
The heat required to melt the 55 g mass of ice = 540 cal/g × 55 g = 29700 cal
The heat required to raise the temperature of a given mass ice (water) = The mass of the ice (water) × The specific heat capacity of the ice (water) × The temperature change
The heat required to raise the temperature of the ice from 0°C to 100°C = 55 × 1 × (100 - 0) = 5,500 cal
The heat required to vaporize a given mass of ice = The Heat of Vaporization × The mass of the ice
The heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal
The total heat required to boil 55 g of ice = 29700 cal + 5,500 cal + 4,400 cal = 39,600 cal
However, we note that the heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal.
The heat required to vaporize the 55 g mass of ice at 100°C = 4,400 cal
Answer:
3.925 mol.
Explanation:
- From the balanced equation:
<em>2 Na₂O₂(s) + 2 H₂O(l) → 4 NaOH(s) + O₂(g)
,</em>
It is clear that 2 moles of Na₂O₂ react with 2 moles of H₂O to produce 4 moles of NaOH and 1 mole of O₂
.
<em>Using cross multiplication:</em>
4 moles of NaOH produced with → 1 mole of O₂
.
15.7 moles of NaOH produced with → ??? mole of O₂
.
<em>∴ The no. of moles of O₂ made =</em> (1 mole)(15.7 mole)/(4 mole) = <em>3.925 mol.</em>
To start this test, you need to identify the variables it presents. As you may already know, there are independent and dependent variables. Independent variables are those that act on a factor, influencing it to generate a result. In the case of this experiment, the independent variable is the completion of the homework. The dependent variable, in turn, is the factor that receives the influence of the independent variable, in this experiment this variable is the final grade you received in the course.
After that you must select a number of students, give them their homework and ask each student to complete a percentage of that amount. An example of this could be that you select 11 students and ask the first to complete 0% of the homework, the second student must complete 10%, the third 20% and so on, and the 11th student must complete 100% of the homework.
after that, note what was the final grade that each student received in the course and make a graph to show the results.
The y-axis of the graph must represent the dependent variable, while the x-axis must represent the independent variable. This way you will show the exact relationship between completing homework and the final grade of the course.
