Answer:
1. a = -10 m/s²
2. a = 1.8 × 10³ km/h²; s = 0.31 km
Explanation:
1.
Given:
Initial speed (u): 30 m/s
Final speed (v): 0 m/s (rest)
Time elapsed (t): 3.0 s
Asked:
Acceleration (a)
Solution:
We will use the following expression.
a = (v-u)/t = (0 m/s - 30 m/s)/3.0 s = -10 m/s²
Final Answer:
a = -10 m/s²
2.
Given:
Initial speed (u): 50 km/h
Final speed (v): 60 km/h
Time elapsed (t): 20 s
Asked:
(a) Acceleration (a)
(b) Distance traveled (s)
Solution:
(a) First, we will convert the time to hours.
20 s × 1 h/3600 s = 0.0056 h
Then, we will use the following expression.
a = (v-u)/t = (60 km/h - 50 km/h)/0.0056 h = 1.8 × 10³ km/h²
(b) We will use the following expression.
s = u × t + 1/2 × a × t²
s = 50 km/h × 0.0056 h + 1/2 × 1.8 × 10³ km/h² × (0.0056 h)² = 0.31 km
Final Answer:
a = 1.8 × 10³ km/h²
s = 0.31 km