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Ray Of Light [21]
3 years ago
15

1. Tyrone is riding his newly bought motorcycle at 30 m/s when he sees a cat on the road ahead. He applied immediately the brake

s and comes to a stop in 3.0 s. What was the acceleration of his motorcycle?
Given:

Asked:

Solution:

Final Answer:

2. A jeepney speeds up from 50 km/h to 60 km/h to overtake a truck. If this requieres 20 s, what is the (a) acceleration and (b) distance traveled by the car?

Given:

Asked:

Solution:

Final Answer:

Pls help​
Chemistry
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

1. a = -10 m/s²

2. a = 1.8 × 10³ km/h²; s = 0.31 km

Explanation:

1.

Given:

Initial speed (u): 30 m/s

Final speed (v): 0 m/s (rest)

Time elapsed (t): 3.0 s

Asked:

Acceleration (a)

Solution:

We will use the following expression.

a = (v-u)/t = (0 m/s - 30 m/s)/3.0 s = -10 m/s²

Final Answer:

a = -10 m/s²

2.

Given:

Initial speed (u): 50 km/h

Final speed (v): 60 km/h

Time elapsed (t): 20 s

Asked:

(a) Acceleration (a)

(b) Distance traveled (s)

Solution:

(a) First, we will convert the time to hours.

20 s × 1 h/3600 s = 0.0056 h

Then, we will use the following expression.

a = (v-u)/t = (60 km/h - 50 km/h)/0.0056 h = 1.8 × 10³ km/h²

(b) We will use the following expression.

s = u × t + 1/2 × a × t²

s = 50 km/h × 0.0056 h + 1/2 × 1.8 × 10³ km/h² × (0.0056 h)² = 0.31 km

Final Answer:

a = 1.8 × 10³ km/h²

s = 0.31 km

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how many molecules of sulfuric acid are in a spherical raindrop of diameter 6.0 mm if the acid rain has a concentration of 4.4 *
Vitek1552 [10]

Answer:

The number of moles =

Moles=4.97\times 10^{-8}

The number of molecules =

Molecules = 2.99\times 10^{16}

Explanation:

Volume of the sphere is given by :

V=\frac{4}{3}\pi r^{3}

here, r = radius of the sphere

radius=\frac{diameter}{2}

radius=\frac{6.0}{2}

Radius = 3 mm

r = 3 mm

1 mm = 0.01 dm (1 millimeter = 0.001 decimeter)

3 mm = 3 x 0.01 dm = 0.03 dm

r = 0.03 dm

<em>("volume must be in dm^3 , this is the reason radius is changed into dm"</em>

<em>"this is done because 1 dm^3 = 1 liter and concentration is always measured in liters")</em>

V=\frac{4}{3}\pi 0.03^{3}

V=\frac{4}{3}\pi 2.7\times 10^{-5}

V=1.13\times 10^{-4}dm^{3}

V=1.13\times 10^{-4}L   (1 L = 1 dm3)

Now, concentration "C"=

C=4.4\times 10^{-4}moles/liter  

The concentration is given by the formula :

C=\frac{moles}{Volume(L)}

This is also written as,

Moles = C\times Volume

Moles=1.13\times 10^{-4}\times 4.4\times 10^{-4}

Moles=4.97\times 10^{-8}moles

One mole of the substance contain "Na"(= Avogadro number of molecules)

So, "n"  mole of substance contain =( n x Na )

N_{a}=6.022\times 10^{23}

Molecules =

Molecule=4.97\times 10^{-8}\times 6.022\times 10^{23}

Molecules = 2.99\times 10^{16} molecules

7 0
3 years ago
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