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Neporo4naja [7]
3 years ago
6

A gallon of gas costs $4.34.Greg puts 12 gallons of gas in his car,He has a 50-dollar bill.Tell how much Greg will have left,or

how much more money he will need.
Mathematics
2 answers:
Leto [7]3 years ago
4 0
$4.34 * 12(gallons) = $52.08

52.08-50 = 2.08

He will need $2.08.
Lerok [7]3 years ago
3 0

Greg will need $2.08 more money to buy 12 gallons of gas.

<h3>Further explanation</h3>

A gallon of gas costs $4.34

Greg puts 12 gallon of gas

Greg has $50

First, we are going to calculate how much money does Greg needs for 12 gallon of gas:

= 12 gallon of gas x cost/gallon

= 12 x 4.34

= 52.08

To multiply the decimal it's just the same way as the whole number multiplication, except for the placement of the decimal point in the answer. For the example

4.34      ⇒ 2 decimal place

<u>     12 x</u>   ⇒ 0 decimal place

 868

<u>434  +</u>

52.08   ⇒ 2 decimal place

By doing the same process as the whole number multiplication we got the answer is 52.08, but don't forget to add the decimal point/decimal place. The first factor has 2 decimal place, the second factor has 0 decimal place, so the answer will have two decimal place (2+0 = 2), by adding the decimal place.

The next step , 12 gallon of gas cost $52.08, if he has $50 so it cost more than the money he has, We are going to do a subtraction:

$52.08

<u>$50.00 </u>-   ⇒ <em>we put zero so we can the borrowing (regrouping)</em>

$  2.08

To subtract a decimal number, we need to line up the decimal point, add trailing zero as a placeholder and then do the subtraction

<h3>Learn more</h3>

Total spend brainly.com/question/12203917

Decimal multiplication brainly.com/question/2124592

Decimal multiplication brainly.com/question/1254534

Keywords: multiplication, decimal multiplication, two digits number additional, additional, subtraction decimal, regrouping

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Complete question is;

Among 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware, which is software programmed into the device. If the firmware is tested in three different pacemakers randomly selected from this batch of 8834 and the entire batch is accepted if there are no failures, what is the probability that the firmware in the entire batch will be accepted? Is this procedure likely to result in the entire batch being accepted?

Answer:

P(All three are not caused by firmware) = 83.84%

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Step-by-step explanation:

We are told that out of the 8834 cases of heart pacemaker malfunctions, 504 were found to be caused by firmware.

Thus,

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P(All three not caused by firmware) = P(first case not caused by firmware) × P(second case not caused by firmware|first case not affected by firmware) × P(third case not caused by firmware|first and second not caused by firmware)

Plugging in the relevant values, we have;

P(All three not caused by firmware) = (8330/8834) × (8329/8833) × (8328/8832)

P(All three are not caused by firmware) = 0.83840506679 ≈ 83.84%

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Answer:

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