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Tju [1.3M]
3 years ago
7

Which equation is equivalent to the given equation?

Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0

Answer:

  D.  (x – 3)^2 = 17

Step-by-step explanation:

We assume you want an equivalent to x^2 -6x = 8.

We can complete the square by adding the square of half the x-coefficient to both sides of the equation.

  x^2 -6x +(-6/2)^2 = 8 +(-6/2)^2

  (x -3)^2 = 17 . . . . simplify

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Evaluate 13+6/y when y = 6​
Anon25 [30]

Answer:

3.166

Step-by-step explanation:

It is not fully done but I put it to the thousandths if you want full answer, it is 3.16666667

8 0
3 years ago
FIND THE AREA OF THE SHADED REGION. SHOW ALL YOUR WORK.
erik [133]

Answer:

he area that is un-shaded is (x-3)(x-6).

The entire area is (2x+2)(3x-4).

Area of the shaded region is:

(2x+2)(3x-4) - (x-3)(x-6) =

(6x2-2x-8) - (x2-9x+18) =

6x2-2x-8-x2+9x-18 =

5x2+7x-26 hopes this help btw (;

3 0
3 years ago
Read 2 more answers
Ginny is studying a population of frogs. She determines that the population is decreasing at an average rate of 3% per year. Whe
sladkih [1.3K]
Hello,

x_{0}=1200

x_{1}=\frac{97}{100}*1200

x_{2}=(\frac{97}{100})^2*1200

x_{3}=(\frac{97}{100})^3*1200
...
x_{n}=(\frac{97}{100})^{n}*1200








4 0
3 years ago
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A ball is thrown in the air from the top of a building. Its height, in meters above ground, as a function of time, in seconds, i
attashe74 [19]

The ball takes approximately a time of 2.041 seconds to reach its maximum height.

<h3>What time does the ball take to reach maximum height?</h3>

The height of the ball as a function of time is modelled by a <em>quadratic</em> equation, the required information can be found by transforming the expression into <em>vertex</em> form:

h = - 4.9 · t² + 20 · t + 12

h = - 4.9 · (t² - 4.082 · t - 2.449)

h + (- 4.9) · (6.615) = - 4.9 · (t² - 4.082 · t + 4.166)

h - 32.414 = - 4.9 · (t - 2.041)²

The ball takes approximately a time of 2.041 seconds to reach its maximum height.

To learn more on quadratic equations: brainly.com/question/1863222

#SPJ1

5 0
2 years ago
3. For the equation-4y = &amp;r, what is the constant of variation? (1 point)<br> ООО<br> 02
alexandr1967 [171]

Answer:

3).

- 4y = 8x \\  \frac{y}{x}  =  \frac{8}{ - 4}  \\  \frac{y}{x} =  - 2 \\ y =  - 2x \\ hence \: constant \: is \:  - 2

4).

y \alpha x \\ y = kx \\ where \: k \: is \: the \: constant \: of \: proportionality \\ when \: y = 24 \: and \: x = 8 \\ substitute \: in \: y = kx \\ 24 = 8k \\ k =  \frac{24}{8}  \\ k = 3 \\ value \: of \: constant = 3

If it was by 10, k = 3 by 10

k = 30

5).

general \: equation \: of \: line  \\ y = mx + c \\ but \: m =  \frac{2}{3}  \: and \: c = 9 \\ substitute \: for \: m \: and \: c \: in \: y = mx + c \\ y =  \frac{2}{3} x + 9 \\ alternatively \\ 3y = 2x + 27

7 0
3 years ago
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