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Tju [1.3M]
3 years ago
7

Which equation is equivalent to the given equation?

Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0

Answer:

  D.  (x – 3)^2 = 17

Step-by-step explanation:

We assume you want an equivalent to x^2 -6x = 8.

We can complete the square by adding the square of half the x-coefficient to both sides of the equation.

  x^2 -6x +(-6/2)^2 = 8 +(-6/2)^2

  (x -3)^2 = 17 . . . . simplify

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20-%202.68%20-%203.57%7D%7B%28%20-%2012.5%20%5Ctimes%200.4%29%7D%20" id="TexForm
Maslowich

Answer:

The answer is 0.125

Step-by-step explanation:

-2.68 - 3.57 ÷ (-12.5 × 4)

-6.25 ÷ (-50)

6.25 ÷ 50 = 0.125

Thus, The answer is 0.125

<em><u>-TheUnknownScientist</u></em>

4 0
3 years ago
Read 2 more answers
Two surveys were independently conducted to estimate a population mean, μ. denote the estimates and their standard errors by x1
lyudmila [28]

Hi there what you need is lagrange multipliers for constrained minimisation. It works like this,

V(X)=α2σ2X¯1+β2\sigma2X¯2

Now we want to minimise this subject to α+β=1 or α−β−1=0.

We proceed by writing a function of alpha and beta (the paramters you want to change to minimse the variance of X, but we also introduce another parameter that multiplies the sum to zero constraint. Thus we want to minimise

f(α,β,λ)=α2σ2X¯1+β2σ2X¯2+λ(\alpha−β−1).

We partially differentiate this function w.r.t each parameter and set each partial derivative equal to zero. This gives;

∂f∂α=2ασ2X¯1+λ=0

∂f∂β=2βσ2X¯2+λ=0

∂f∂λ=α+β−1=0

Setting the first two partial derivatives equal we get

α=βσ2X¯2σ2X¯1

Substituting 1−α into this expression for beta and re-arranging for alpha gives the result for alpha. Repeating the same steps but isolating beta gives the beta result.

Lagrange multipliers and constrained minimisation crop up often in stats problems. I hope this helps!And gosh that was a lot to type!xd

3 0
3 years ago
30 = x/5<br><br><br><br><br>dnjdjrjrjejjeuehehehehrhhr​
MatroZZZ [7]

Answer:

x = 150

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
2=2 (lw+lh+wh) solve for w
kirza4 [7]
Solve for w.

2=2(lw+lh+wh)

Flip the equation.

2hl+2hw+2lw=2

Add -2hl to both sides.

2hl+2hw+2lw+−2hl=2+−2hl

2hw+2lw=−2hl+2

Factor out variable w.

w(2h+2l)=−2hl+2

Divide both sides by 2h+2l.

w(2h+2l) / 2h+2l=−2hl+2 / 2h+2l

w=−hl+1/h+l

5 0
3 years ago
Select the two binomials that are factors of this trinomial.
ivann1987 [24]

Answer:

B and D

Step-by-step explanation:

Given

x² - x - 12

Consider the factors of the constant term (- 12) which sum to give the coefficient of the x- term (- 1)

The factors are - 4 and + 3 , since

- 4 × 3 = - 12 and - 4 + 3 = - 1 , then

x² - x - 12 = (x - 4)(x + 3) ← in factored form

7 0
3 years ago
Read 2 more answers
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