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aleksandrvk [35]
3 years ago
15

Two shapes are shown below, one isosceles triangle and one rectangle. The dimensions can be represented by algebraic expressions

, as shown in the diagram below. They both have the same area. Find the numerical value of the perimeter of the isosceles triangle. show full calculations please

Mathematics
1 answer:
liberstina [14]3 years ago
8 0

Answer:

Perimeter of Isosceles Triangle = 16 units

Step-by-step explanation:

Area of rectangle is given by the formula;

Area = 1/2 × base × height

From the diagram, base = 6x - 6 and height = 6x - 8

Thus,Area = 1/2 × (6x - 6) × (6x - 8)

Area = (3x - 3)(6x - 8) = 18x² - 42x + 24

Secondly, area of rectangle is given by;

Area = length x breadth

So, area of rectangle in question = (6x - 9)(3x - 2) = 18x² - 39x + 18

We are told both the area of the triangle and the rectangle are the same, so let's equate both areas;

18x² - 42x + 24 = 18x² - 39x + 18

18x² will cancel out and rearranging, we have;

24 - 18 = 42x - 39x

6 = 3x

x = 6/3

x = 2

Plugging 2 for x for the height and base of the triangle, we have;

base = 6(2) - 6 and height = 6(2) - 8

Base = 6 and height = 4

So,let's find the slant height of the isosceles triangle.

Dividing the base by 2,we have; 6/2 = 3

So,using Pythagoras theorem, let the slant height be h, so we have;

h² = 3² + 4²

h² = 9 + 16

h² = 25

h = √25

h = 5

2 slant sides of isosceles triangle are the same. So perimeter = 5 + 5 + 6 = 16 units

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4. Which ordered pair is a solution of 3y + 2 = 2x - 5?
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we determine that none of the ordered pair is a solution of  3y\:+\:2\:=\:2x\:-\:5  as none of the ordered pairs satisfy the equation.

Step-by-step explanation:

Considering the equation

3y\:+\:2\:=\:2x\:-\:5

  • Putting (-5,2) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(2\right)\:+\:2\:=\:2\left(-5\right)\:-\:5

8=-15         ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (0,-5) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(-5\right)\:+\:2\:=\:2\left(0\right)\:-\:5

-13=-5       ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (5,1) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(1\right)+\:2\:=\:2\left(5\right)-\:5

5\:=-5          ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (7,5) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(5\right)+\:2\:=\:2\left(7\right)-\:5\:\:

17=9          ∵ L.H.S ≠ R.H.S

FALSE

From the above calculations, we determine that none of the ordered pair is a solution of  3y\:+\:2\:=\:2x\:-\:5  as none of the ordered pairs satisfy the equation.

4 0
3 years ago
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