-4 < -12 would be my answer, just from looking at it. If you write it out on a number line, the number -4 is higher than -12. The higher the negative number, the lower it is on the line. So, -4 is greater than -12, not lower than.
44 molars she recieved is the range of mummy’s revived
Sum/difference:
Let
This means that
Now, assume that 
is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that was rational, which proves that the sum/difference of the two given terms was irrational
Multiplication/division:
The logic is actually the same: if we multiply the two terms we get
if again we assume x to be rational, we have
But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.
Answer:
(A) - (5)
(B) - (4)
(C) - (1)
(D) - (2)
Step-by-step explanation:
(A) We are given the polynomial (x+4)(x−4)[x−(2−i)][x−(2+i)]
(5) The related polynomial equation has a total of four roots; two roots are complex and two roots are real.
(B) We are given the polynomial (x+i)(x−i)(x−2)³(x−4).
(4) The related polynomial equation has a total of six roots; two roots are complex and one of the remaining real roots has a multiplicity of 3.
(C) We are given the polynomial (x+3)(x−5)(x+2)²
(1) The related polynomial equation has a total of four roots; all four roots are real and one root has a multiplicity of 2.
(D) We are given the polynomial (x+2)²(x+1)²
(2) The related polynomial equation has a total four roots; all four roots are real and two roots have a multiplicity of 2. (Answer)
