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Allushta [10]
3 years ago
13

Blank percent of 50 shirts is 35 shirts

Mathematics
1 answer:
kirill [66]3 years ago
4 0

x\% \times 50 = 35 \\  \dfrac{x}{100}  \times 50 = 35 \\ x = 35 \div 50 \times 100 \\ x = 70

Answer check :
50 \times  \dfrac{70}{100}  \\  = 35

Answer : 70%

Hope this helps. - M
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-3 (4 - 2y) = 24<br> Solve for "y"<br> Best answer get rewarded <br> Please show work
arlik [135]
-3(4-2y)=24

Apply distributive property

-12+6y=24

Add 12 to both sides

6y=36

Divide both sides by 6

y=6
6 0
3 years ago
When 2 fractions refer to the same whole and have the same denominator explain why you can compare only the numerators
Mrrafil [7]
One way ti find the common denominatir is to check ti see if ine denominator is a factor to the other deniminator if it is then the deniminator can be used as the common denominator when the two deniminators are the same compare the numerators
4 0
3 years ago
What is the exponential regression equation that fits these data? y x 1 4 2 8 3 27 4 85 5 250 6 600
Volgvan

Answer:

its is C because the other ones are obvious wrong. So it has to be C plus i did this test.

Step-by-step explanation:

5 0
2 years ago
Need help with my homework ​
Volgvan

Answer:

\displaystyle y=\frac{16-9x^3}{2x^3 - 3}

\displaystyle y=-\frac{56}{13}

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3

Simplify the radical with the cube:

\displaystyle x^3=\frac{3y+16}{2y+9}

Multiply by 2y+9

\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)

Simplify:

\displaystyle x^3(2y+9)=3y+16

Operate the parentheses:

\displaystyle x^3(2y)+x^3(9)=3y+16

\displaystyle 2x^3y+9x^3=3y+16

Subtract 3y and 9x^3:

\displaystyle 2x^3y - 3y=16-9x^3

Factor y out of the left side:

\displaystyle y(2x^3 - 3)=16-9x^3

Divide by 2x^3 - 3:

\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}

ii) To find y when x=2, substitute:

\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}

\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}

\displaystyle y=\frac{16-72}{16- 3}

\displaystyle y=\frac{-56}{13}

\mathbf{\displaystyle y=-\frac{56}{13}}

8 0
2 years ago
What would the answer be because I already tried everything and I just can’t get it
Mrac [35]

Answer:

e = 56

Step-by-step explanation:

Use cross multiplication.

28 * 14 = 7e

Simplify

392 = 7e

Divide each side by 7

e = 56.

5 0
3 years ago
Read 2 more answers
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