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mezya [45]
3 years ago
14

If a piece of sea floor moved 50km in 5 million years what is the yearly rate in motion

Mathematics
1 answer:
Zanzabum3 years ago
6 0

The answer is 100,00 km per year
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Four hundred fifty thousand in standard form
lutik1710 [3]

Answer:

From India

4.5×10⁵

standard form is written above

7 0
1 year ago
What is the midpoint of the line segment with endpoints ( 3.5,2.2) and (1.5,-4.8)?
Fantom [35]

Answer:

Option A) (2.5,-1.3) is correct

The midpoint of the given line segment is M=(2.5,-1.3)

Step-by-step explanation:

Given that the line segment with end points (3.5, 2.2) and (1.5, -4.8)

To find the mid point of these endpoints midpoint formula is M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

Let (x_1,y_1) be the point (3.5, 2.2) and (x_2, y_2) be the point (1.5, -4.8)

substituting the points in the formula

M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

M=\left(\frac{3.5+1.5}{2}, \frac{2.2-4.8}{2}\right)

=\left(\frac{5}{2}, \frac{-2.6}{2}\right)

=\left(2.5,-1.3\right)

Therefore M=(2.5,-1.3)

The midpoint of the given line segment is M=(2.5,-1.3)

8 0
3 years ago
The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu
m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. \mu=23.50

\sigma=5

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let \overline{x} be the sample mean.

Formula : z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

Then, the probability that the sample mean is at least $25.00 will be :-

P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0
3 years ago
You went to a bake sale and bought a whole bunch of
MakcuM [25]

Answer:

If cookies are for $1 and brownies are for $2, let number of cookies = x and number of brownies = y

∴ $1*(x*1) + $2*(y*1) = $13

Step-by-step explanation:

1) You can buy 4 brownies for $2 each = 2*4 = $8

The rest you can buy cookies = 5 cookies = $5

$8+$5=$13

2) You can buy 5 brownies and 3 cookies = $10+$3 = $13

3) You can buy 3 brownies and 7 cookies = $6+$7=$13

Equation: -

If cookies are for $1 and brownies are for $2, let number of cookies = x and number of brownies = y

∴ $1*(x*1) + $2*(y*1) = $13

7 0
3 years ago
Find the area of the figure. Round to the nearest hundredth if necessary
ki77a [65]
The area of the figure :)

8 0
3 years ago
Read 2 more answers
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