3 years ago

If a piece of sea floor moved 50km in 5 million years what is the yearly rate in motion

Mathematics

1 answer:

Zanzabum3 years ago

6 0

The answer is 100,00 km per year

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Calculate (A⃗ ×B⃗ )⋅C⃗ for the three vectors A⃗ with magnitude A = 5.08 and angle θA = 25.6 ∘ measured in the sense from the +x

alexgriva [62]

Answer:

(A⃗ ×B⃗ )⋅C⃗ = - 76.415

Step-by-step explanation:

First we need to calculate (A⃗ ×B⃗ ) :

(A⃗ ×B⃗ ) = A.B.sin (α).n

Where A is the magnitude of A⃗

Where B is the magnitude of B⃗

Where α is the angle between A⃗ and B⃗ = 63.9 - 25.6 = 38.3

Finally n is the vector orthogonal to A⃗ and B⃗

n magnitude is 1 and his direction is given by the right hand-rule

so n = ( 0 , 0 , 1 )

(A⃗ ×B⃗ ) = A.B.sin (α).n = 5.08 . 3.94 . sin (38.3) . (0 , 0 , 1 ) = (0,0,12.4)

C⃗ can be written as C.(0,0,-1) because of his +z - direction

C.(0,0,-1) = 6.16.(0,0,-1) = (0,0,-6.16)

(A⃗ ×B⃗ )⋅C⃗ = (0,0,12.4).(0,0,-6.16) = -76.41480787 = -76.415

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3 years ago

A machine fills 75 bottles of water each minute. Write an equation to represent the number of bottles b of water the machine can

Len [333]

Answer:

b = 75m

Step-by-step explanation:

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3 years ago

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A ship sails 95 km on a bearing of 140 degrees,than further on 102km on a bearing of 260degrees,and than returns directly to its

sammy [17]

Answer:

1. 98.7 km

2. 303.5 degree

Step-by-step explanation:

Using the alternate angle, the angle at B will be 50 + 10 = 60 degree.

To calculate the length AC of the returning journey, use cosine formula to calculate it.

To find the bearing of the returning journey, use sine rule to calculate it.

Please find the attached file for the solution

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3 years ago

What is the product in simplest form?<br> 3/5 x 2/3 = ?

boyakko [2]

Answer:

2/5 or 0.4

Step-by-step explanation:

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Write the Quotient for the following 5 1/3 ÷2

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

51/3/2=51x2/3=102/3=34

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2 years ago

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